Da Shari wants to rearrange the four sweaters, two coats, and five jackets that are in her closet. If she puts a sweater first a
nd a jacket last, how many different ways can she arrange them?
1 answer:
Solution:
Fabric possessed by Da. Shari = 4 Sweaters + 2 Coats + 5 Jackets= 11 in all
Arrangement that Da Shari wants to arrange 4 Sweaters + 2 Coats + 5 Jackets is to put "a sweater first and a jacket last".
After putting a sweater first and jacket last , total fabric which needs to be arranged is (3 Sweaters + 2 Coats + 4 Jackets)=9 in all.
Total number of possible arrangement = (1 sweater) × [9 fabric=(3 Sweaters + 2 Coats + 4 Jackets) arrangement] × (1 Jackets)
= 1! × 9 ! × 1!
= 9 !
= 9 × 8 × 7× 6× 5× 4× 3×2×1
= 362,880 ways
You might be interested in
9.2 because you have to multiply it by 10 to get the answer.
4x - 5y = 40
4x = 40 + 5y
x = 10 + 5/4y
The x intercept is 10.
<span>Round the value of r to 3 decimal places = Answer is True</span>
Answer:
Step-by-step explanation:
For the first one it is 4n^2-4
