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Doss [256]
3 years ago
13

Mae bought 15 football cards and 18 baseball cards. She separated them into 3 equal groups. How many sports cards are in each gr

oup?
Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
6 0
Oooo i can help :D... i believe the answer is 11... that because... 15+18=33 divided by 3 equals 11!
wolverine [178]3 years ago
3 0

Answer: There are 11 sports cards in each group.

Step-by-step explanation:

Given: The number of football cards Mae has = 15

The number of baseball cards Mae has = 18

Since, She separated them into 3 equal groups.

Therefore, The number of football cards each group has = \frac{15}{3}=5

The number of baseball cards each group has = \frac{18}{3}=6

The number of sports cards in each group = 5+6=11

Hence, there are 11 sports cards in each group.

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Consider the following set of vectors. v1 = 0 0 0 1 , v2 = 0 0 3 1 , v3 = 0 4 3 1 , v4 = 8 4 3 1 Let v1, v2, v3, and v4 be (colu
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Answer:

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c_1\left[\begin{array}{c}0\\0\\0\\1\end{array}\right] +c_2\left[\begin{array}{c}0\\0\\3\\1\end{array}\right] +c_3\left[\begin{array}{c}0\\4\\3\\1\end{array}\right] +c_4\left[\begin{array}{c}8\\4\\3\\1\end{array}\right] =\left[\begin{array}{c}0\\0\\0\\0\end{array}\right]

Then, the augmented matrix of the system is

\left[\begin{array}{cccc}0&0&0&8\\0&0&4&4\\0&3&3&3\\1&1&1&1\end{array}\right]

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\left[\begin{array}{cccc}1&1&1&1\\0&3&3&3\\0&0&4&4\\0&0&0&8\end{array}\right]

This matrix is in echelon form. Then, now we apply backward substitution:

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