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Maslowich
4 years ago
13

Describe the graph of y > mx, where m > 0.

Mathematics
1 answer:
pentagon [3]4 years ago
6 0
Linear equation. (y = mx+b) The value of m is 0.5 and b is zero, so this is the graphof the equation y = 0.5x+0 which simplifies to y = 0.5x. This is a simple linear equation and so is a straight line whose slope is 0.5
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Solve this equation: <br> x/5=-7
Marianna [84]

Answer:

x/5 = -7

Step-by-step explanation:

x = -35

I used a calculator pls let me know if im incorrect

3 0
3 years ago
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One student says a decimal can reach one million. The other says it cannot how can he defend his claim.
Lena [83]
If the number is big enough there can be up to an infinite number of decimals

5 0
3 years ago
Side of the triangle below has been extended to form an exterior angle of 135 find the value of X
sattari [20]

Answer:

x = 45

Step-by-step explanation:

x + 135 = 180  {Linear pair}

        x = 180 - 135          {Subtract 135 from both sides}

        x = 45

6 0
3 years ago
Seven friends eat out and decide to split the bill. Three friends only brought cash so they pay Henry who in turn pays for their
Thepotemich [5.8K]

If seven friends eat out and split a bill, we must first figure out how much each person would pay individually. To find this number, we need to divide the total bill by the total number of people. $100. 10/7 = 14.3, so each person payed $14.3 individually. If three friends only brought cash so they pay Henry to pay for their portion on credit card, then Henry would pay for those three friends and himself on a credit card, or just 4 times how much one of them payed. Since each of them payed 14.3, then to find out how much Henry payed on credit card, we need to multiply 14.3 by 4 which gives us our answer of $57. 12

8 0
4 years ago
HELP!!
Liono4ka [1.6K]

Answer:

Part 1: The polygon ABCDE reflected across y-axis to get the polygon MNOPQ. So, the polygon ABCDE congruent to polygon MNOPQ.

Part 2: The vertices of polygon VWXYZ are V(1, 3), W(-1, 7), X(-7, 7), Y(-5, 3), and Z(-3, 1).

Step-by-step explanation:

Part 1:

The vertices of the polygon ABCDE are A(2, 8), B(4, 12), C(10, 12), D(8, 8), and E(6, 6).

The vertices of the polygon MNOPQ are M(-2, 8), N(-4, 12), O(-10, 12), P(-8, 8), and Q(-6, 6).

We need to find the transformation or sequence of transformations that can be performed on polygon ABCDE to show that it is congruent to polygon MNOPQ.

The relation between the vertices of ABCDE and MNOPQ are defined as

(x,y)\rightarrow (-x,y)

It means the polygon ABCDE reflected across y-axis to get the polygon MNOPQ. So, the polygon ABCDE congruent to polygon MNOPQ.

Part 2:

If polygon MNOPQ is translated 3 units right and 5 units down, then

(x,y)\rightarrow (x+3,y-5)

M(-2,8)\rightarrow V(-2+3,8-5)=V(1,3)

N(-4,12)\rightarrow W(-4+3,12-5)=W(-1,7)

O(-10,12)\rightarrow X(-10+3,12-5)=X(-7,7)

P(-8,8)\rightarrow Y(-8+3,8-5)=Y(-5,3)

Q(-6,6)\rightarrow Z(-6+3,6-5)=Z(-3,1)

Therefore the vertices of polygon VWXYZ are V(1, 3), W(-1, 7), X(-7, 7), Y(-5, 3), and Z(-3, 1).

6 0
3 years ago
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