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valina [46]
3 years ago
12

Drew does push-ups every three days starting in January 3.He does sit ups every four days starting on January 4.on which days in

January will he do both push ups and sit ups?use words,numbers,or models to justify your answer.
Mathematics
1 answer:
shepuryov [24]3 years ago
3 0
January 12 because he will be on his 4th day of push ups and his 3rd day of situps
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Please help I need the answer ASAP!!!!!
zloy xaker [14]

h(t) = 80t - 16t²

Ground level is h(0) = 0

We want to solve for t:

h(t)= 0

80t - 16t² = 0

16t(5 - t) = 0

t = 0 or t = 5

Answer: 5 seconds

3 0
3 years ago
Read 2 more answers
I will mark you the brainiest for the correct answer, please be correct, Have a good day and take care, thanks. ( VIEW THE IMAGE
Gwar [14]
First error is that the legs are a and b so a should be x and b is 6 and c is 10 the second error is at the end they did not take the square root to get x by itself the real answer should be
X^2 +6^2=10^2
X^2+36=100
X^2 =64
X=8
6 0
3 years ago
100m world record was completed at an average speed of 37.6 km/h. work out this speed in meters per second?
pickupchik [31]

Step-by-step explanation:

1 km = 1000 m

1 hour = 3600 s

so,

37.6 km = 37,600 m (still per hour or per 3600 s).

in 1 second now that is

37600/3600 = 10.44444444... m/s

4 0
2 years ago
The ages of armadillos are normally distributed, with a mean of 14 years and a standard deviation of 1.2. Approximately what per
vovangra [49]

Answer:

Percentage of armadillos between 13 and 17 years = 79.052%f using Standard Normal Distribution Tables

Step-by-step explanation:

As we know from normal distribution: z(x) = (x - Mu)/SD

where x = targeted value; Mu = Mean of Normal Distribution; SD = Standard Deviation of Normal Distribution

Therefore using given data: Mu = 14, SD = 1.2 we have z(x) by using z(x) = (x - Mu)/SD as under:

Approach 1 using Standard Normal Distribution Table:

z for x=17: z(17) = (17-14)/1.2 gives us z(17) = 2.5

z for x=13: z(13) = (13-14)/1.2 gives us z(13) = -0.83

Afterwards using Normal Distribution Tables we find the probabilities as under:

P(17) using z(17) = 2.5 gives us P(17) = 99.379%

Similarly we have:

P(13) using z(13) = -0.83 gives us P(13) = 20.327%

Finally in order to find out the probability between 17 & 13 years we have:

Percentage of armadillos between 13 and 17 years = P(17) - P(13) = 99.379% - 20.327% = 79.052%

The standard normal distribution table is being attached for yours easiness.

Approach 2 using Excel or Google Sheets:

P(17) = norm.dist(17,14,1.2,1)

P(13) = norm.dist(13,14,1.2,1)

Percentage of armadillos between 13 and 17 years = { P(17) - P(13) } * 100

Download pdf
4 0
3 years ago
Read 2 more answers
Which of the following expressions can be used to find the perimeter of the shape? All sides are the same length. A. 15 x 15. B.
umka21 [38]

Answer:

B and D

Step-by-step explanation:

This must be a six sided figure

A. 15 x 15.  This would be area

B. 6 x 15.   This is the sum of six sides of 15

C. 15 + 6.  This is the sum of 2 sides of different length

D. 15 + 15 + 15 + 15 + 15 + 15.  This is the sum of six sides of length 15

6 0
3 years ago
Read 2 more answers
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