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otez555 [7]
3 years ago
12

Kyle spent $155 on 9 items at the mall. Shirts were $15 and jeans were $20. How many of each did he buy?

Mathematics
2 answers:
soldi70 [24.7K]3 years ago
7 0

Answer

4 jeans and 5 shirts should be right

Olenka [21]3 years ago
4 0
She bought 5 shirts and 4 jeans
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The general manager, marketing director, and 3 other employees of CompanyAare hosting a visitby the vice president and 2 other e
zubka84 [21]

Answer:

Following are the answer to this question:

Step-by-step explanation:

Let, In the Bth place there are 8 values.

In point a:

There is no case, where it generally manages its next groom is = 7 and it will be arranged in the 2, that can be arranged in 2! ways. So, the total number of ways are: \to 7 \times 2= 14\\\\ \{(1,2),(2,1),(2,3),(3,2),(3,4),(4,3),(4,5),(5,4),(5,6),(6,5),(6,7),(7,8),(8,7),(7,6)\}\\\therefore required probability:

= \frac{14}{8!}\\\\= \frac{14}{8\times7 \times6 \times 5 \times  4 \times 3\times 2 \times 1 }\\\\= \frac{1}{8\times6 \times5 \times 4 \times 3}\\\\= \frac{1}{8\times6 \times5 \times 4 \times 3}\\\\=\frac{1}{2880}\\\\=0.00034

In point b:

Calculating the leftmost position:

\to \frac{7!}{8!}\\\\\to \frac{7!}{8 \times 7!}\\\\\to \frac{1}{8}\\\\\to 0.125

In point c:

This option is false because

\to P(A \cap B) \neq P(A) \times P(B)\\\\\to \frac{12}{8!} \neq \frac{14}{8!}\times \frac{1}{8}\\\\\to \frac{12}{8!} \neq \frac{7}{8!}\times \frac{1}{4}\\\\

3 0
3 years ago
A basket of fruit contains 4 bananas, 3 apples, and 5 oranges. You intend to draw a piece of fruit from the basket, keep it, dra
gregori [183]

Answer:

The probability that the fruits will be selected in the order of banana then apple then orange is 0.1094

Step-by-step explanation:

The given information are;

The number of bananas = 4

The number of apples = 3

The number of oranges = 5

The total number of fruits are 4 + 3 + 5 = 12

The probability of selecting a banana, p(b) = 4/12 = 1/3

The probability of selecting an apple, p(a) = 3/12 = 1/4

The probability of selecting an oranges, p(o) = 5/12

The probability of selecting one banana, then one apple, then one orange, in that order, from the basket with replacement is the product of the individual probabilities found as follows;

p(p(b) then p(a) then p(o)) =

The number o

The probability that the first fruit is a banana = ₁₁C₃×(1/3)^(3)×(2/3)^8 = 0.2384

The probability that the second fruit is an apple = ₁₁C₃×(1/4)^(3)×(3/4)^8 = 0.258

The probability that the third fruit is an apple = ₁₁C₃×(5/12)^(3)×(7/12)^8 = 0.16

The total probability = 0.2384 + 0.285 + 0.16 = 0.657

The number of ways in which the three can be selected = 3 × 2 × 1 = 6 ways

Therefore, the probability that the fruits will be selected in the order of banana then apple then orange = 0.657/6 = 0.1094.

4 0
3 years ago
-5c = 30<br> Forgot the steps of solving it
Pavlova-9 [17]
Divide 30 by -5. Or 30/-4=C. C=-6
6 0
3 years ago
Similar right triangles <br> Find the value of x.
julsineya [31]
X^2 = 9.4 = 36
x = 6
good luck
6 0
2 years ago
The show 14 / 6 on a number line
Serhud [2]
I drew this by hand. sorry I it does not help.

3 0
3 years ago
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