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nata0808 [166]
3 years ago
14

Two congruent squares overlap at the midpoint of their sides. If a square has a side of 24 cm, what is the area of the figure?

Mathematics
1 answer:
fiasKO [112]3 years ago
8 0
I think it's the double of the area of one of the squares
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The distance around the middle of a sphere (the circumference) equals 37.699 in. what is the surface area of the sphere?
podryga [215]

To solve this problem you must apply the proccedure shown below:

1. Clear the radius from the formula for the circumference of a circle and substitute values, as following:

C=2\pi r\\ r=C/2\pi \\ r=37.699in/2\pi \\ r=5.99in

2. Substitute the radius calculated into the formula for calculate the surface area of the sphere:

SA=4\pi r^{2} \\ SA=4\pi(5.99in^{2})\\ SA=450.88in^{2}

The answer is: 450.88in^{2}

5 0
3 years ago
A mirror frame in the shape of an oval is shown below. The ends of the frame form semicircles: (5 points)
guapka [62]

Answer:

696.265 inches

Step-by-step explanation:

Radius = 27/2 = 13.5

2 semicircles + 2 lengths

(3.14 × 13.5²) + 2(62)

696.265 inches

4 0
2 years ago
F-7/g = h for f<br>solve for f
gregori [183]
(f - 7)/g = h
f - 7 = gh
f = gh + 7
5 0
3 years ago
Please Help
Jlenok [28]

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Dot plot is useful when we have a small number of individual values. In this case we can visualize how many times each individual value occurred in the data. This is useful when the number of values in the data is less.

In the given scenario, we have 12 values in total ranging from 1 to 5. So making a dot plot would be the best choice. A histogram would not be useful in this case.

Therefore, the correct answer is option D. Dot plot, because a small number of scores are reported individually

7 0
3 years ago
Read 2 more answers
Can anyone solve 9, 10, 11, 12, and 13 I'm stuck on those problems, I already solved 14, 15, and 16 on paper.
ddd [48]

Answer:

9. x>-4 or x≥1

10. a<2 or a≥-5

11. v≤7 or v≥-4

12. k≥5 or k<8

13. n>6.8 and n≤9

Step-by-step explanation:

9. -2x-7>1

-2x>8

x>-4

x-2≥-1

x≥1

10.a/-2 <-1

a<2

-4a+3≥23

-4a≥20

a≥-5

11. 6v+38≤-4

6v≤-42

v≤7

2(v+3)≥-2

2v+6≥-2

2v≥-8

v≥-4

12. 4(1-k)≥-16

4-4k≥-16

-4k≥-20

k≥5

7-6k<-41

-6k<-48

k<8

13. 10n-9>-59

10n>-68

n>6.8

n-6≤3

n≤9

4 0
2 years ago
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