Given:
In △ABC is a right angle triangle.
AC is 6 units longer than side BC.

To find:
The length of AC.
Solution:
Let the length of BC be x.
So, Length of AC = x+6
According to the Pythagoras theorem, in a right angle triangle

△ABC is a right angle triangle and AC is hypotenuse, so

![[\because (a+b)^2=a^2+2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a%2Bb%29%5E2%3Da%5E2%2B2ab%2Bb%5E2%5D)
Subtract 68 from both sides.



Divide both sides by 2.

Splitting the middle term, we get




Side cannot be negative, so x=2 only.
Now,



Therefore, the length of AC is 8 units.
The length of line segment AB by observation if the diagram in the task content is; 14.
<h3>
What is the length of line segment AB?</h3>
It follows from the task content that the line segment MN can be considered as parallel to line segment AB. This follows from the fact that the vertices of triangle MNO are midpoints of the line segments of triangle ABC.
Consequently, it can be concluded that line segment AB is twice the length of line segment MN and hence, BC = 2 × 7 = 14.
Read more on triangle line segments;
brainly.com/question/3573606
#SPJ1
Answer:
c
Step-by-step explanation:
Using Pascal's triangle, the expansion, although EXTREMELY lengthy, will help you find the 7th term. I am going to type out the expansion only up til the 7th term (although there are actually 10 terms because we are raised to the power of 9). If you would like to learn how to use Pascal's Triangle for binomial expansion, you will need to visit a good website that explains it because it's just too difficult to do it via this website.
The expasion is as follows (up to the 7th term):

That last term is the 7th term. You find out its value by multiplying all the numbers together and adding on the c^3d^6. Again those come from Pascal's triangle, and it's one of the coolest math things ever. I encourage you to take the time to explore how it works.
What’s the question though? we need to know what the question is to answer :) ❤️
the lateral area and total area of regular pyramid with a square base is 130