2.48 can be rounded pretty much any number between 2.45 to 2.5
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Answer:
a 10 yd 2ft 7 in
b 10 yd 1 ft 2 in
c 99 yd
d. 4840 sq yd 7 sq ft 119 sq in
Step-by-step explanation:
a. 2 ft. 5 in. +
9 yd. 3 ft. 2 in.
---------------------
9 yd 5ft 7 in
but 3 ft = 1yd
9 yd 5ft 7 in
+1yd - 3ft
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10 yd 2ft 7 in
b. 4 yd. 8 in
+ 6 yd. 6 in.
----------------------
10 yd 14 in
but 12 in = 1ft
10 yd 14 in
+ 1ft - 12 in
---------------------
10 yd 1 ft 2 in
c. 29 yd. 2 ft. 11 in.
55 yd. 1 ft. 10 in.
+ 13 yd. 1 ft. 3 in.
--------------------------
97 yd 4 ft 24 in
12 in = 1ft
24 in = 2ft
97 yd 4 ft 24 in
+2ft - 24 in
--------------------------------
97 yd 6ft
3 ft = 1yd
6f = 2yd
97 yd 6ft
+2yd - 6ft
---------------------
99 yd
d. 4,839 sq. yd. 8 sq. ft. 139 sq. in.
+ 7 sq. ft. 124 sq. in.
--------------------------------------------------
4839 sq yd 15 sq ft 263 sq in
12*12 = 144 sq in = 1 sq ft
4839 sq yd 15 sq ft 263 sq in
+ 1 sq ft - 144 sq in
--------------------------------------------------
4839 sq yd 16 sq ft 119 sq in
3ft * 3 ft = 9 sq ft = 1 sq yd
4839 sq yd 16 sq ft 119 sq in
+1 sq yd - 9 sq ft
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4840 sq yd 7 sq ft 119 sq in
1/2*3*4=6
Explanation:
The height is 3 cm and the base is 4cm.
I believe 5 is there to trick you. The bottom Is always the base and the straight line going vertically is always the height.
1/2*3*4=6
Answer:
Part A: 2.8 miles
Part B: 16.8 miles
Step-by-step explanation:
First, solve for how many miles Ted jogged in 1 day:
Variable x = number of miles
11.2/4 = x/1
Cross multiply
11.2 × 1 = 4 × x
11.2 = 4x
Divide both sides by 4
2.8 = x
He jogged 2.8 miles every day.
To find how many miles Ted would jog in 6 days, simply multiply his miles per day by the number of days he will jog:
2.8 miles × 6 days = 16.8 miles in 6 days
Answer:
Assuming ur looking for the circumference
its 24.94pi
(the last one)
Step-by-step explanation:
Brainliest would be eappreciated :)
