The two types of energy changes that occur are heat and light changes.
Answer:
444 L
Explanation:
According to Archimedes the buoyancy force is equal to the weight of the displaced substance. In this case, the displaced substance is Air. So to calculate the lifting power of Helium, start with the weight of air in volume
Since the Helium itself has weight, we need to use the difference in density between air and helium.
We know that the density of air is 1.2 
Density of Helium is 0.1787 
To lift a object of 1 pound which is equal to 0.453 kg we need

helium There is 1000 liters in a 
So the required volume of helium= 0.444×1000=444 L
The volume you would expect the gas to occupy if the pressure is increased to 40
The kpa would be 50 liters
Answer:
The volume of 0.80 grams of O2 is 0.56 L
Explanation:
Step 1 : Data given
Mass of O2 = 0.80 grams
Molar mass of O2 = 32 g/mol
STP = 1 mol, 1atm, 22.4 L
Step 2: Calculate moles of oxygen
Moles of O2 = Mass of O2 / molar mass of O2
Moles O2 = 0.80 grams / 32 g/mol
Moles O2 = 0.025 moles
Step 3: Calculate volume of O2
1 mol = 22.4 L of gas
0.025 moles = 0.025*22.4L = 0.56 L
The volume of 0.80 grams of O2 is 0.56 L