An object with a negative acceleration could NEVER have a positive velocity. a. TRUE b. FALSE

What is the solution to the problem expressed to the correct number of significant figures

quester [9]

I don't know what the problem is, but here are some rues to help you out:

All non-zero figures are significant
When a zero falls between non-zero digits, that zero is significant.
When a zero falls after a decimal point, that zero is significant.
When multiplying and dividing significant figures, the answer is limited to the number of sig figs equal to the least number of sig figs in the problem.
When adding and subtracting, the answer is limited to the number of decimal places in the number with the least number of decimal places.

4 0

3 years ago

Which of the following is a way in which water resources are consumed? a. drinking b. industry c. business d. all of the above P

kirill [66]

d.

all of the above is the correct answer

3 0

3 years ago

Students are designing an experiment to test the law of conservation of mass using the following materials: 10 g baking soda, 30

Ivan

it would be 50ml hope th

8 0

2 years ago

A 5.76 liter sample of a gas at 22.00C mL 748 torr pressure was heated to a final volume of 17.28 liters, with the pressure rema

timama [110]

Answer:

The final temperature was 612 °C

Explanation:

Charles's law relates the volume and temperature of a certain amount of ideal gas, maintained at a constant pressure, using a constant of direct proportionality. In this law, Charles says that at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. That is, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

$\frac{V}{T}=k$

When you want to study two different states, an initial and a final one of a gas and evaluate the change in volume as a function of temperature or vice versa, you can use the expression:

$\frac{V1}{T1} =\frac{V2}{T2}$

In this case:

V1= 5.76 L
T1= 22 °C= 295 °K (Being 0°C=273°K)
V2=17.28 L
T2=?

Replacing:

$\frac{5.76 L}{295 K} =\frac{17.28 L}{T2}$

Solving:

$T2 =\frac{17.28 L}{\frac{5.76 L}{295 K}}=\frac{17.28 L*295 K}{5.76 L}$

T2= 885 °K = 612 °C

The final temperature was 612 °C

5 0

3 years ago

Water is A. Acidic B. Basic C. Neutral

Mariana [72]

Water acts as an acid (donates H+) when it reacts with a stronger base, say sodium hydroxide. Water acts as a base (accepts H+) when it reacts with a stronger acid, say hydrochloric acid. If the medium is water, water, having a pH of 7, is considered neutral.

8 0

3 years ago