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Scorpion4ik [409]
3 years ago
11

How many valence electrons does oxygen have? A. 2 B. 6 C. 8 D. 16

Chemistry
1 answer:
AleksandrR [38]3 years ago
8 0

Oxygen has 6 valence electrons, so B

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As the temperature of a sample of a radioactive element decreases, the half-life will
ki77a [65]

As the temperature of a sample of a radioactive element decreases, the half-life will remain the same

<u>Explanation:</u>

Half-life is defined as the time needed for half of the opening material to modify or decay. Half-lives can be estimated from measures on the variation in the mass of a nuclide and the period it gets to occur. In the period of that substance's half-life, half of the primary nuclei will decompose.

Although chemical changes were raced up or delayed down by varying factors such as temperature, concentration, etc, these factors do not affect half-life. Each radioactive isotope will have its unique half-life that is independent of any of these factors.

5 0
3 years ago
Question 2 (1 point)
Alex73 [517]

Answer:

35 amu

Explanation:

In an atom, only masses of protons and neutrons are relevant. electrons are so small in size that their masses are negligible.

The mass of 1 proton/neutron is 1amu.

6 0
3 years ago
How many grams of HNO3 it is required to play 8.75gr N2O<br> 4ZN + 10HNO3-4ZN ( NO3 ) 2 + N20 + 5H2O
Y_Kistochka [10]
Molar mass

 HNO₃ = 63.02 g/mol

N₂O = 44.013 g/mol

The balanced equation is :

<span>4 Zn + 10 HNO₃  = 4 Zn(NO₃)₂ + N₂O + 5 H₂O
</span>
10 * 63.02 g HNO₃-----------> 44.013 g N₂O
        ?   HNO₃ -----------------> 8.75 g N₂O

Mass HNO₃ =  8.75 * 10 * 63.02 / 44.013

Mass HNO₃ = 125 g 

hope this helps!
4 0
4 years ago
Bronsted lowry base that are not considered Arrhenius bases
Elenna [48]

Answer: An example is <u>sodium ethoxide (NaOCH2CH3) dissolved in ethanol (CH3CH2OH).</u>

Hope this helps!

3 0
2 years ago
Find the empirical and molecular formula for a molar mass of 60.10g/mol; 39.97% carbon 13.41% hydrogen: 46.62% nitrogen
PSYCHO15rus [73]
Assuming we have 100g, this means that

39.97g Carbon * 1 mol / 12 g = 3.33 mol Carbon
13.41g Hydrogen * 1 mol/1 g = 13.41 mol Hydrogen
46.62g Nitrogen * 1 mol / 14 g = 3.33 mol Nitrogen
Dividing everything by 3.33, we get

1 mol Carbon, 4.03 mol Hydrogen, 1 mol Nitrogen.

Empirical formula is CH4N

<span>The mass of the empirical formula is
12 + 4 + 14 = 30

Since the molar mass is double, we multiply all our subscripts

The molecular formula is C2H8N2

The answers to this question are </span><span>an empirical formula of CH4N</span> and a molecular formula of C2H8N2 .
5 0
3 years ago
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