find the area of the base which is 8*8=64 in^2
then the triangles one is 2*[(6*4)/2)]= 24 in^2 and theres 4 of them so times 4
24*4=96 in^2
then add and u get 160 in^2
Answer:
x
Step-by-step explanation:
equals 4 you can do rest
Answer:
BK=39/7
Step-by-step explanation:
because NQZ~CBK
so BK/QZ = TZ/KF
(4x+1)/(2x+7) = 27/45 = 3/5
5(4x+1) = 3(2x+7)
20x + 5 = 6x + 21
14x = 16
x = 8/7
=> BK = 4(8/7)+1 = 39/7
Answer:
Line segment: AD (without arrow)
Ray: BA (with one sided arrow)
Rays with common endpoint: AC and AD (with one sided arrow)
Intersection: AE (double sided arrow)
Collinear points: B, A, C
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