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Alex_Xolod [135]
4 years ago
11

For line graphs and bar graphs, the values measured by the vertical axis

Mathematics
2 answers:
mestny [16]4 years ago
5 0

Answer:

Horizontal

Step-by-step explanation:

ZanzabumX [31]4 years ago
4 0

Answer:

horizontal axis

Step-by-step explanation:

its a chart measured by x and y.

x meaning side to side and y meaning up or down.

and in any equation x makes y or usually y is defined by x.

Example: y = mx + b

so y = vertical and x = horizontal

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How can the distributive property be used to find 4 x 875? draw an array.
Llana [10]
First what is 4*5 then 4*7 then 4*8

4 0
3 years ago
QUESTÃO 01
Korvikt [17]

Responder:

2³

5⁴

10³

a^6

Explicação passo a passo:

Quando um certo valor é multiplicado repetidamente,

Por exemplo,

a * a * a * a = a⁴ (a multiplicado 4 vezes)

Por isso,

2 x 2 x 2 = 2³

5 x 5 x 5 x 5 = 5⁴

10 x 10 x 10 = 10³

a x a x a x a x a x a = a^6

5 0
3 years ago
3(n+4)=21 what does n =?
Brilliant_brown [7]

Answer:

3.

Step-by-step explanation:

3(n + 4) = 21

3n + 12 = 21

3n = 21 - 12 = 9

n = 3.

7 0
3 years ago
Read 2 more answers
Please help me with this.
Tom [10]

Answer:

28.26

Step-by-step explanation:

Area of a circle = pi (radius)^2 so...

A=3.14(9) = 28.26, which is your first choice

7 0
4 years ago
Using Cramer’s Rule, what is the value of y in the system of linear equations below?
Vadim26 [7]

for the system of equations

a_1x+b_1y=c_1 \\a_2x+b_2y=c_2

the three matrices needed to use Cramer's Rule are:

D=\left[\begin{array}{cc}a_1&b_1\\a_2&b_2\end{array}\right] \\\\D_x=\left[\begin{array}{cc}c_1&b_1\\c_2&b_2\end{array}\right] \\\\D_y=\left[\begin{array}{cc}a_1&c_1\\a_2&c_2\end{array}\right].

To use Cramer's Rule we have to calculate the three determinants listed below of the matrices listed below.

D=\left[\begin{array}{cc}2&5\\-3&-2\end{array}\right] \\\\D_x=\left[\begin{array}{cc}-13&5\\3&-2\end{array}\right] \\\\D_y=\left[\begin{array}{cc}2&-13\\-3&3\end{array}\right] .

The value of the determinants are shown below.

det(D)=(2)(-2)-(-3)(5)=-4+15=11\\det(D_x)=(-13)(-2)-(3)(5)=26-15=11\\det(D_y)=(2)(3)-(-3)(-13)=6-39=-33\\

The value of y is \frac{det(D_y)}{det(D)}=-\frac{33}{11} =-3..

3 0
4 years ago
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