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3 years ago

HELP pleaseeeeeeeeeeeeeeeee

Mathematics

2 answers:

natulia [17]3 years ago

6 0

I don’t really know this but ima take my best shot

Yanka [14]3 years ago

3 0

2 rows of geraniums and 4rows of the other one

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Find the length of the missing side of the perimeter is 30ft

Svetach [21]

Answer:

5ft

Step-by-step explanation:

7 + 10 + 8 = 25

subtract that form 30

25-30

Thane you get

so the answer is

5!!!!!

also plz mark me brainliest

4 0

3 years ago

In 2004, Cindy had $4000 in a mutual fund account. In 2005, the

gtnhenbr [62]

6,250
1,000/4,000 = 25/100
25/100 = x/5,000
x = 1,250

5,000 + 1,250 = 6,250

4 0

3 years ago

find the area of a circke with a radius of 9 mm. round to the nearest tenth. use 3.15 or 22/7 for Pi.

GREYUIT [131]

Answer:

254.3 mm^2

Step-by-step explanation:

Area of a circle: A = π*r^2

π (pi) = 3.14

r (radius) = 9 mm

Substitute 3.14 for pi and 9 for radius:

A = π*r^2

A = 3.14*9^2

A = 3.14*81

A = 254.34 mm^2

Round to the nearest tenth:

254.34 ==> 254.3

Therefore, our final answer is 254.3 mm^2

Hope this helps!

6 0

2 years ago

Compute the values of dy and Δy for the function y=e^(2x)+6x given x=0 and Δx=dx=0.03.

Maksim231197 [3]

Answer:

dy = 8·dx
Δy = 0.24

Step-by-step explanation:

The derivative of your function is ...

y' = dy/dx = 2e^(2x) +6

At x=0, the value is ...

y'(0) = 2e^0 +6 = 8

dy = 8·dx

Δy = y'(0)·Δx

Δy = 8(.03)

Δy = 0.24

6 0

3 years ago

Suppose you do not know the population mean fee charged to H&R Block customers last year. Instead, suppose you take a sample

puteri [66]

Answer:

i $\to$ a

$n = 96040000$

i $\to$ b

$n_1 =24010000$

i $\to$ c

$n_2 =41602500$

ii $\to$ a

$E = 58.16$

ii $\to$ b

$291.84 < \mu < 408.16$ \

ii $\to$ c

There is insufficient evidence to conclude that the analyst is right because the population mean fee by the analyst does not fall within the confidence interval

Step-by-step explanation:

From the question we are told that

The sample size is $n = 8$

The sample mean is $\= x = \$ 350$

The sample standard deviation is $\$ 100$

Considering question i

i $\to$ a

At $E = 0.02$

given that the confidence level is 95% = 0.95

the level of significance would be $\alpha =1-0.95 = 0.05$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{ \alpha }{2} } = 1.96$

So the sample size is mathematically evaluated as

$n = [ \frac{Z_{\frac{\alpha }{2} } * \sigma }{E} ]^2$

=> $n =[ \frac{ 1.96 * 100}{ 0.02} ]^2$

=> $n = 96040000$

i $\to$ b

At $E_1 = 0.04$ and confidence level = 95% => $\alpha_1 = 0.05$ => $Z_{\frac{\alpha_1 }{2} } = 1.96$

$n_1 = [ \frac{Z_{\frac{\alpha_2 }{2} } * \sigma }{E_1} ]^2$

=> $n_1 =[ \frac{ 1.96 * 100}{ 0.04} ]^2$

=> $n_1 =24010000$

i $\to$ c

At $E_2 = 0.04$ confidence level = 99% => $\alpha_2 = 0.01$

The critical value of $\frac{\alpha_2 }{2}$ from the normal distribution table is

$Z_{\frac{ \alpha_2 }{2} } = 2.58$

=> $n_2 = [ \frac{Z_{\frac{\alpha_2 }{2} } * \sigma }{E_2} ]^2$

=> $n_2 =[ \frac{ 2.58 * 100}{ 0.04} ]^2$

=> $n_2 =41602500$

Considering ii

Given that the level of significance is $\alpha = 0.10$

Then the critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

substituting values

$E = 1.645 * \frac{100 }{\sqrt{8} }$

$E = 58.16$

Generally the 90% confidence interval is mathematically evaluated as

$\= x - E < \mu < \= x + E$

=> $350 - 58.16 < \mu < 350 + 58.16$

=> $291.84 < \mu < 408.16$

So the interpretation is that there is 90% confidence that the mean fee charged to H&R Block customers last year is in the interval .So there is insufficient evidence to conclude that the analyst is right because the population mean fee by the analyst does not fall within the confidence interval.

8 0

3 years ago