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DerKrebs [107]
3 years ago
9

A landscaping company charges $100 plus $15 per hour. another company charges $75 plus $17 per hour. how long is a job that cost

s the same no matter which company is used?
Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
4 0
Let h = number of hours

100 + 15h = 75 + 17h        solve for h
          100 = 75 + 2h          subtract 15h from both sides
             25 = 2h                 subtract 75 from both sides
          12.5 = h                   divide both sides by two

You would have to work 12 hours and 30 minutes for both companies to cost the same.
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Help me pls i'm on a timer!!!!
e-lub [12.9K]

Answer:

C, 360

Step-by-step explanation:

Interior angle sums can be found using the equation (N=-2)*180, where N equals the number of sides of the polygon.

4 0
3 years ago
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I'm stuck on this one! Help please?
zepelin [54]
Expand 

(4a + 12 = 12 + 4a)

Cancel 4a on both sides

12 = 12

Since both sides are equal there are infinitely many solutions

Process of elimination, cross out d) no solution. But I would best go with C)
7 0
4 years ago
Which of the following best describes the perpendicular lines?
AysviL [449]

Answer:

A perpendicular line is a line that meets a 90 degree angle.

Step-by-step explanation:

Think of the letter L

the top stick of the letter is perpendicular to the bottom stick and it makes a 90 degree angle.

Thats the best way I can explain it.

Hope this helps and please mark me brainliest if it did :)

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4 years ago
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If m∠ADB=(6x−4)° and m∠BDC=(4x+24)°, find the value of x such that ∠ADC is a right angle.
spayn [35]

To make ∠ADC is a right angle, value of x will be 7.

From given figure, it is observed that Angle ADC is combination of two angles ADB and BDC.

                ∠ADC=∠ADB+∠BDC

Since, ∠ADC is right angle.

 So,  ∠ADC=90 degree

       90=∠ADB+∠BDC

     6x-4+4x+24=90\\     10x+20=90\\      10x=70\\       x=7

Learn more:

brainly.com/question/20158593

8 0
3 years ago
Two workers finished a job in 12 days. How long would it take each worker to do the job by himself if one of the workers needs 1
Lorico [155]

Two workers finished a job in 7.5 days.

How long would it take each worker to do the job by himself if one of the workers needs 8 more days to finish the job than the other worker?

let t = time required by one worker to complete the job alone

then

(t+8) = time required by the other worker (shirker)

let the completed job = 1

A typical shared work equation

7.5%2Ft + 7.5%2F%28%28t%2B8%29%29 = 1

multiply by t(t+8), cancel the denominators, and you have

7.5(t+8) + 7.5t = t(t+8)

7.5t + 60 + 7.5t = t^2 + 8t

15t + 60 = t^2 + 8t

form a quadratic equation on the right

0 = t^2 + 8t - 15t - 60

t^2 - 7t - 60 = 0

Factor easily to

(t-12) (t+5) = 0

the positive solution is all we want here

t = 12 days, the first guy working alone

then

the shirker would struggle thru the job in 20 days.

8 0
3 years ago
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