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3 years ago

Why is it essential that the regulatory mechanisms that activate glycogen synthesis also deactivate glycogen phosphorylase?

Biology

1 answer:

Marta_Voda [28]3 years ago

5 0

Answer:

There are two pathways occur in the same cellular compartment, and, if both are on at the same time, a futile ATP hydrolysis cycle results. Using the same mechanism to turn them on/off or off/on is highly efficient.

- "Glycogen Phosphorylase" activity can be allosterically controlled ATP and G6P allosteric inhibitors, AMP allosteric activator as well as, controlled through covalent modification, phosphorylation and via hormones.

- Reaction Catalyzed by Glycogen Synthase:

The activity of glycogen synthase is subject to the same type of covalent modification as glycogen phosphorylase, however, the response is opposite. Glycogen Synthase is activated by G6P. It is also controlled via hormones.

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Bile is released into which body organ in response to the consumption of fat? bile is released into which body organ in response

notsponge [240]

The answer to this question would be the small intestine.

The bile is released into the small intestine to help to digest fat. Bile secretion will bind the fat so it will turn into many small groups. This will increase the surface area for the enzyme to work.
the esophagus is just a tunnel and stomach are not digesting fat. the large intestine is absorbing water.

7 0

4 years ago

Read 2 more answers

Three examples of selective breedings, explain?

ANEK [815]

Artificial Selection is a form of selection in which humans actively choose which traits should be passed onto offspring. Humans have used selective breeding long before Darwin's Postulates and the discovery of genetics. Farmers chose cattle with beneficial traits such as larger size or producing more milk, and made them breed; and although they may have known nothing about genes, they knew that the beneficial traits could be heritable. The farmers selected for certain traits in their cattle and probably noticed that the offspring were becoming more and more productive with each generation. Scientists study these traits and spend a lot of time calculating how heritable these traits can be. The more these traits are expressed in the offspring (i.e. size, milk production, etc), the more heritable these traits are said to be. Hunting is also a form of artificial selection, with the genes that humans "want" (i.e. - the biggest buck with the most points, the largest fish, etc.) being removed from the gene pool, allowing the less "wanted" genes to pass on to the next generation by increasing their odds of mating when compared to the hunted specimens.

Hope this will help.

7 0

4 years ago

narvez 5. Everyone in Dobby's family has a long nose and they brag that they are from a purebred line. Viola has a stubby nose.

mote1985 [20]

Assuming a single diallelic gene coding for the trait and expressing complete dominance, the phenotypes, genotypes, and probabilities of getting each of them vary according to the parentals' genotypes. See the options below.

---------------------------------

Since I do not have the genotypes from #2, I will provide different potential scenarios for this question.

I advise you to check on them and see which one matches the genotype from #2.

Let us assume a single diallelic gene is coding for the trait and expresses complete dominance.

<h3 /><h3>SCENARIO 1 ⇒ long nose is the dominant trait</h3>

Let us say that

L is the dominant allele and codes for long nose

l is the recessive allele and codes for stubby nose

Since long nose is dominant over stubby nose

LL and Ll ⇒ long nose

ll ⇒ stubby nose

If Dobby comes from a purebred family and has long nose, his genotype must be LL.

And if Viola has stubbi nose, her genotype must be ll.

Cross 1

Parentals) LL x ll

Gametes) L L l l

Punnett square) L L

l Ll Ll

F1) Genotype ⇒ 100% heter0zyg0us Ll

Phenotype ⇒ 100% long-nosed

There is 100% chances for a child to have a long nose

There is 0% chances for a child to have a stubby nose

These children are not purebred

**********

<h3>SCENARIO 2 ⇒ Stubby nose is the dominant trait</h3>

Let us say that

S is the dominant allele and codes for stubby nose

s is the recessive allele and codes for long nose

Since stubby nose is dominant over long nose

SS and Ss ⇒ stubby nose

ss ⇒ long nose

If Dobby comes from a purebred family and has long nose, his genotype must be ss.

And if Viola has stubbi nose, her genotype must be either SS or Ss.

There are two possible crosses.

Cross 1 : Violet is h0m0zyg0us dominant SS

Parentals) SS x ss

Gametes) S S s s

Punnett square) S S

s Ss Ss

F1) Genotype ⇒ 100% heter0zyg0us Ss

Phenotype ⇒ 100% stubby-nosed

There is 100% chances for a child to have a stubby nose

There is 0% chances for a child to have a long nose

These children are not purebred

Cross 2: Violet is heter0zyg0us, Ss

Parentals) Ss x ss

Gametes) S s s s

Punnett square) S s

s Ss ss

F1) Genotype ⇒ 50% heter0zyg0us Ss and 50% h0m0zyg0us recessive ss

Phenotype ⇒ 50% stubby-nosed and 50% long-nosed

There is 50% chances for a child to have a stubby nose

There is 50% chances for a child to have a long nose

These children are not purebred

----------------------------

You can learn more about single gene crosses at

brainly.com/question/12653314?referrer=searchResults

7 0

2 years ago

Lipids are a poor source of stored energy. lipids are a poor source of stored energy.

valentina_108 [34]

B. False it’s the only source of stored energy we got

6 0

3 years ago

If a heterozygous woman without hemophilia had children with a man with hemophilia, what is the chance that their first child wi

dybincka [34]

Answer:

1/2

Explanation:

let the alleles of the heterozygous woman without hemophilia be = Xhx

And the alleles of the man with hemophilia be XhY

If both XhY × Xhx; we have:

Xh Y

Xh XhXh XhY

x Xhx xY

XhXh and XhY are affected by the diseases

Xhx is a carrier

xY is normal

∴ the probability(chance) that their first child will have the disease is 2/4 of the total offspring

=1/2

∴ the probability (chance) that their first child will have the disease is 1/2

3 0

4 years ago