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3 years ago

What conclusion can you make about the skeleton structure of these two organisms

Chemistry

2 answers:

Inessa05 [86]3 years ago

7 0

The answer would be the first one

Jobisdone [24]3 years ago

5 0

Hello

The conclusion we can make about these two organisms,

Is C. They're different species with no evolutionary relationship.

Thank you, and Goodbye.

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The following shows the precipitation reaction of barium chloride (BaCl₂) and sodium hydroxide (NaOH):

Nadya [2.5K]

Answer:

The answer to your question is:

a) BaCl2

b) 0.8208 g

c) yield = 85.3 %

Explanation:

BaCl₂(aq) + NaOH(aq) ----> Ba(OH)₂(s) + 2NaCl(aq)

Data

a) 1 g of BaCl₂

1 g of NaOH

MW BaCl2 = 137 + (35.5x2) = 208 g

MW NaOH = 23 + 16 + 1 = 40 g

208 g of BaCl2 ------------- 1 mol

1 g of BaCl2 ------------- x

x = ( 1 x 1) / 208 = 0.0048 mol of BaCl2

40 g of NaOH ------------ 1 mol

1 g of NaOH ------------ x

x = (1 x 1) / 40

x = 0.025 mol of NaOH

The ratio BaCl2 to NaOH is 1:1 (in the equation)

But experimentally we have 0.0048 : 0.025, so the limiting reactant is BaCl2, because is in lower concentration.

1 mol of BaCl2 -------------- 1 mol of Ba(OH)2

0.0048 mol --------------- x

x = (0.0048 x 1) / 1

x = 0.0048 mol of Ba(OH)2

MW Ba(OH)2 = 137 + 32 + 2 = 171 g

171 g of Ba(OH)2 -------------------- 1 mol

x -------------------- 0.0048 mol

x = (0.0048 x 171) / 1

x = 0.8208 g

c)Data

Ba(OH)2 = 0.700 g

% yield = 0.700 / 0.8208 x 100

% yield = 85.3

Sorry, i don't understand this question

6 0

3 years ago

Who discovered electrons using Crookes tube?

andrey2020 [161]

Answer:

William Crookes????????????????

4 0

3 years ago

Read 2 more answers

A source of zinc metal can be zinc ore containing zinc(II) sulfide. The ore is roasted in pure oxygen to produce the oxide and t

morpeh [17]

Answer:

32.7 grams of Zn will remained in the crucible after cooling.

Explanation:

$2ZnS+3O_2 \rightarrow 2ZnO + 2SO_2$ ..[1]

$ZnO+C\rightarrow Zn+CO$ ..[2]

Adding [1] + 2 × [2] we get:

$2ZnS+3O_2+2C \rightarrow 2Zn + 2CO+2SO_2$ ..[3]

Moles of ZnS in crucible = 0.50 mol

According to reaction [3]. 2 moles of ZnS gives 2 moles of Zn.

Then 0.50 moles of ZnS will give:

$\frac{2}{2}\times 0.50 mol=0.50 mol$ of Zn.

Mass of 0.50 moles of Zn =

= 0.50 mol × 65.4 g/mol =32.7 g

32.7 grams of Zn will remained in the crucible after cooling.

5 0

4 years ago

Determine the molar mass of an unknown monoprotic acid to two decimal places if 20.01 ml of a 0.098 m naoh solution were used to

natita [175]

By using the following formula we can calculate the volume;
C₁V₁ = C₂V₂
C₁ = concentration of starting solution = 0.098m
V₁ = volume of starting solution that is needed for titration = 20.01ml
C₂ = Desired concentration of final solution = ?
V₂ = desired volume of final solution = 0.215g = 0.215ml
Now putting the values in the formula;
0.098 x 20.01 = C₂ x 0.215
C₂ = 0.215 / 1.96098 = 0.109m = 0.11m
Thus, the answer is 0.11m.

4 0

3 years ago

Which of these is correct regarding Thomson's cathode ray observations

uysha [10]

Answer:

Explanation:

8 0

4 years ago