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Chemistry

1 answer:

Ede4ka [16]3 years ago

4 0

Answer:

1.) 7

2.) 5

3.) stable

4.) 5A

5.) 5

6.) The properties would be more stable to property of phosphorous because same group and valenve electronics and they also have same chemical

Explanation:

The rest i dont know

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KNO3(s) --> K+(aq) + NO3-(aq)

ella [17]

Answer:

KNO₃(s) + 35,1 kJ → K⁺(aq) + NO₃⁻(aq)

Explanation:

In the reaction:

KNO₃(s) → K⁺(aq) + NO₃⁻(aq)

The heat absorbed for the reaction (Because the temperature decreases) is:

Q = C×m×ΔT

Where C is specific heat (4,18J/g°C); m is mass (100g); ΔT is (30,0°C-21,6°C = 8,4°C)

Replacing:

Q = 4,18J/g°C×100g×8,4°C

Q = 3511 J

Now, moles of KNO₃ are:

10,1g×(1mol / 101g) = 0,1 moles.

Heat of solution in kJ/mol is:

3,511 J / 0,1 mol = 35,1 kJ

As the heat was absorbed for the reaction, right answer is:

KNO₃(s) + 35,1 kJ → K⁺(aq) + NO₃⁻(aq)

That means the reaction needs the heat to occurs.

I hope it helps!

6 0

3 years ago

A car travels 10km in 10 min so what is the average

soldi70 [24.7K]

The answer is 60 km/h..

4 0

2 years ago

Read 2 more answers

The equilibrium reaction below has the Kc = 0.254 at 25°C. If the temperature of the system at equilibrium is decreased to 0°C,

tia_tia [17]

Answer:

The equilibrium shifts towards reagents

Explanation:

Is known $Kc=\frac{[products]}{[reagents]}$ rised to the power of their number of moles in the balanced reaction. When you have a system at equilibrium with Kc < 1, it means [products] < [reagents] and the system needs energy to react, so if you decrease tempeture the equilibrium shifts towards reagents and less products will be created.

This efect can be discribed with Van´t Hoff equation: $ln(\frac{K1}{K2}) =-\frac{dH}{R} (\frac{1}{T1} -\frac{1}{T2} )$ where we can see that if we decrease temperature (this is T2<T1) in consecuense K2<K1 and reaction doesn´t happen.