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Aleks [24]
4 years ago
14

X=r-h/y solve for h and then for r

Mathematics
2 answers:
WINSTONCH [101]4 years ago
7 0
X=(r-h)/y
xy=r-h
xy-r=-h
r-xy=h

x=(r-h)/y
xy=r-h
xy+h=r
alexandr402 [8]4 years ago
7 0

Answer:

r=x+\frac{h}{y}

Step-by-step explanation:

X=r-h/y

x=r-\frac{h}{y}

Solve the equation for 'r'

To solve the equation for 'r', we add the fraction on both sides.

x+\frac{h}{y}=r-\frac{h}{y}+\frac{h}{y}

So right side we are left with 'r'

r=x+\frac{h}{y}

We got the 'r' alone. So we solve for 'r'

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Mr. Hayden's Bible class collected $11
ki77a [65]

This is the only way I can think of this mathematically. This took a good 20 minutes for me. You need to guess and check. Like try 17 quarters, 50 nickels, and 37 dimes etc. until you get 11.00. My numbers are mathematically correct but we both know you cant have 18.909 quarters so. lol

Answer:

Quarters: 18.909

Nickels: 49.818

Dimes: 37.818

Somewhere around those numbers.

Step-by-step explanation:

$11.00 total in coins

Nickel = $0.05

Dime = $0.10

Quarter = $0.25

(n*0.05) + (d*0.10) + (q*0.25)

Solve the equation for q.

q=\frac{1}{2} d

(n*0.05) + (d*0.10) +( \frac{1}{2} d *0.25)

Simplify the expression.

9d + 2n = 440

d - n = -12

Multiply both sides of the equation by -9.

-9d + 9n = 108

9d + 2n = 440

Sum the equations vertically to eliminate at least one variable.

11n = 548

n=\frac{548}{11}

Substitute the given value of n into the equation d - n = -12

d-\frac{548}{11} =-12

d=\frac{416}{11}

Substitute the given value of n into the equation q=\frac{1}{2} d

q=\frac{1}{2} *\frac{416}{11}

q=\frac{208}{11}

Finally

d=\frac{416}{11}        d = 37.818

n=\frac{548}{11}        n = 49.818

q=\frac{208}{11}        q = 18.909

6 0
3 years ago
Pl hell any thing is appreciated I will give Brainly
Zarrin [17]

Answer:

First one and last one

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
*25 points!*
mariarad [96]
Pick 2 pairs of equations t<span>hen use addition and subtraction to eliminate </span>the same variable<span> from both pairs of equations then it is left with 2 variables 
</span>Pick two pairs
<span><span>4x - 3y + z = - 10</span><span>2x + y + 3z = 0
</span></span>eliminate the same variable from each system
<span><span>4x - 3y + z = - 10</span> 
<span>2x + y + 3z = 0</span> 

<span>4x - 3y + z = - 10</span> 
<span>-4x - 2y - 6z = 0</span> 

<span>-5y - 5z = - 10</span> 

<span>2x + y + 3z = 0</span> 
<span>- x + 2y - 5z = 17</span> 

<span>2x + y + 3z = 0</span> 
<span>-2x + 4y - 10z = 34</span> 

<span>5y - 7z = 34
</span></span>Solve the system of the two new equations:
<span><span>-5y - 5z = - 10</span> 
<span>5y - 7z = 34</span> 

<span>-12z = 24</span> 
which is , <span>z = - 2</span> 

<span>-5y - 5(- 2) = - 10</span> 
<span>-5y = - 20</span> 
wich is , <span>y = 4
</span></span>substitute into one of the original equations
<span>- x + 2y - 5z = 17</span> 
<span>- x + 2(4) - 5(- 2) = 17</span> 
<span>- x + 18 = 17</span> 
<span>- x = - 1</span> 
<span>x = 1</span> 
<span>which is , </span><span>(x, y, z) = (1, 4, - 2)</span><span> 
</span>Does 2(1) + 4 + 3(- 2) = 0<span> ? Yes</span><span>

</span>
7 0
3 years ago
Sasha can run at an average speed of 9 3/4 min/mi. She runs at this speed for 68 1/4 min.
miv72 [106K]
9 3/4 = 39/4 mi/m

68 1/4 = 273/4 min

39/4 mutiply by 273/4 = 10647 / 16 mi = 665.4 mi
4 0
3 years ago
Answer for both pleaseeeeeeeeeee
Oksi-84 [34.3K]

Answer:

0 and yes

Step-by-step explanation:

Let a=6m where m is any integer since a is divisible by 6. (a+12)/3=(6m+12)/3=2m+4 which is also an integer. The remainder is 0.

Since n is divisible by 3, n can be written as 3a, where a is any integer and m can be written as 2b, where b is any integer. n*m+12=6ab+12 which is divisible by 2.

7 0
3 years ago
Read 2 more answers
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