ok what do u need help with I don't see anything
Answer:
(x-6) (2x+1)
Step-by-step explanation:
1) move everything over to the left side, so subtract 11x and 6.
2x^2 -11x - 6 = 0
2)multiply 2(a term) with -6 (c term)
x^2 -11x -12
3) factor and find what multiples to -12 and adds up to -11. in this case its -12 and positive 1
(x-12) (x+1)
4) divide -12 and 1 by the original a term (2)
(x-6) (x+1/2)
5) move the denominator of 2 over to the x.
(x-6) (2x+1)
To answer the problem above, convert the given angle to an equivalent angle with the unit of degrees.
(13π / 12 rad) x (360° / 2π) = 195°
We can solve this by directly inputting the value in our scientific calculators. The answer is approximately -0.2588.
Answer:
p= 44
/9
(44 over 9)
Step-by-step explanation:
Answer:
x² + 2x + [3\x - 1]
Step-by-step explanation:
Since the divisor is in the form of <em>x - c</em>, use what is called <em>Synthetic Division</em>. Remember, in this formula, -c gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:
1| 1 1 -2 3
↓ 1 2 0
------------------
1 2 0 3 → x² + 2x + [3\x - 1]
You start by placing the <em>c</em> in the top left corner, then list all the coefficients of your dividend [x² + 5x - 36]. You bring down the original term closest to <em>c</em> then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder, which in this case is a 3, so what you is set the divisor underneath the remainder of 3. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an x², 2 becomes <em>2x</em><em>,</em><em> </em>and the remainder of 3 is set over the divisor, giving you the other factor of <em>x² + 2x + [3\x - 1]</em>.
If you are ever in need of assistance, do not hesitate to let me know by subscribing to my channel [USERNAME: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.
