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Lana71 [14]
3 years ago
15

Please help me out!!!!!!!!!!!

Mathematics
1 answer:
Eddi Din [679]3 years ago
4 0

Answer:

256

Step-by-step explanation:

Each of the terms is multiplied by -4

1 * -4 = -4

-4 * -4 = 16

16 * -4 = -64

-64 * -4 = 256


Hope this helps! :)

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Describe the graph of a function g by observing the graph of the base function f ? ​
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Answer:

Choice 3 is your answer

Step-by-step explanation:

The format of the function when you move it side to side or up and down is

f(x) = (x - h) + k,

where h is the side to side movement and k is up or down.  The k is easy, since it will be positive if we move the function up and negative if we move the function down from its original position.

The h is a little more difficult, but just remember the standard form of the side to side movement is always (x - h).  If our function has moved 3 units to the left, we fit that movement into our standard form as (x - (-3)), which of course is the same as (x + 3).  Our function has moved up 5 units, so the final translation is

g(x) = f(x + 3) + 5, choice 3 from the top.

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3 years ago
Please help me with this quadratic equation question! I always give out 5 stars, thanks and brainliest to people that help me wi
ss7ja [257]

Answer:

p=25,\\q=12

Step-by-step explanation:

In (ax+b)(cx+d)=acx^2+bcx+dax+bd, notice the third term of the quadratic in standard form is formed entirely by b\cdot d.

Therefore, in 12x^2 - 13x - 7175 = (x-p) (qx + 287):

-p\cdot287=-7175,\\-p=\frac{-7175}{287},\\p=\fbox{$25$}.

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3 0
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4 0
3 years ago
Read 2 more answers
Eliminate the parameter:<br> x = 2cost-1 y = 3sint+ 4
adell [148]

Answer:

Hi,

Step-by-step explanation:

\left\{\begin {array} {ccc}x&=&2*cos(t)-1\\y&=&3*sin(t)+4\\\end{array}\right.\\\\\\\left\{\begin {array} {ccc}\dfrac{x+1}{2}&=&cos(t\\\dfrac{y-4}{3}&=&sin(t)\\\end{array}\right.\\\\Squaring\\\\\boxed{(\dfrac{x+1}{2})^2+(\dfrac{y-4}{3})^2&=1}\\

The curve is an ellipse having (-1,4) as center and half-axis (2 and 6)

8 0
2 years ago
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Lubov Fominskaja [6]

Answer:

y = 2x - 11.

Step-by-step explanation:

Use the point-slope form of the straight line.

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5 0
1 year ago
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