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Rainbow [258]
3 years ago
14

Which table represents a function?

Mathematics
1 answer:
Arisa [49]3 years ago
3 0

Answer:

first one

Step-by-step explanation:

same x value can't have more than one y value

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Which of the following are operations in the algebra of sets?
postnew [5]

Answer:

Union and Intersection

Step-by-step explanation:

We know that the algebra of sets define the properties and laws of the sets.

The basic operations of sets are,

Union, Intersection, Complement of a set and Equality of sets.

Since, the operations addition, subtraction, multiplication and division are the basic arithmetic operations of numbers.

i.e. they are not in the algebra of sets.

So, we get that out of the given options, the operations in algebra of sets are Union and Intersection.

7 0
3 years ago
Solve the equation.<br><br> NEED HELP ASAP!!!
Andrej [43]
Answer

x = 32

explanation
6 0
3 years ago
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Melissa got two puppies, Ben and Sadie.
MA_775_DIABLO [31]

Answer:

x = 4y - 20

Step-by-step explanation:

x = Sadie's weight

y = Ben's weight

x = 4(y - 5)

x = 4y - 20

7 0
3 years ago
Show that cos(3x) = cos3(x) − 3 sin2(x)cos(x). (Hint: Use cos(2x) = cos2(x) − sin2(x) and the cosine sum
otez555 [7]

<u>Step-by-step explanation:</u>

To prove:

\cos 3x=\cos^3x-3\sin^2 x\cos x

Identities used:

\cos(A+B)=\cos A\cos B+\sin A\sin B      ......(1)

\sin 2A=2\sin A\cos A        ........(2)

\cos 2A=\cos^2A-\sin^2 A     .......(3)

Taking the LHS:

\Rightarrow \cos 3x=\cos (x+2x)

Using identity 1:

\Rightarrow \cos (x+2x)=\cos x\cos 2x-\sin x\sin 2x

Using identities 2 and 3:

\Rightarrow \cos x(\cos ^2x-\sin^2 x)-\sin x(2\sin x\cos x)\\\\\Rightarrow \cos^3x-\sin^2x\cos x-2\sin^2 x\cos x\\\\\Rightarrow \cos^3x-3\sin^2x\cos x

As, LHS = RHS

Hence proved

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3 years ago
Who can answer this first POINTS
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Answer:

$1.45

Step-by-step explanation:

4 0
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