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Lady_Fox [76]
3 years ago
7

ILL GIVE BRAINLIST! plus 12 points!

Mathematics
2 answers:
Masja [62]3 years ago
8 0

Answer:

its B

Step-by-step explanation:

i took the quiz

kozerog [31]3 years ago
4 0

Answer:

B

Step-by-step explanation:

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Determine the positive real root of ln(x²) = 0.7
timama [110]

Answer:

i have no clue.

Step-by-step explanation:

i am very tired while doing a math link so please, don't give me any trouble with this :)

5 0
3 years ago
Which equation can be used to find x, the length of the hypotenuse of the right triangle?
zysi [14]

Answer:

Hypotenuse ^2= long leg^2 + short leg^2.

Step-by-step explanation:

THIS EQUATION ONLY WORKS FOR A RIGHT TRIANGLE

3 0
3 years ago
Read 2 more answers
If (-2,3), 3x-2ky+4=0 find the value of k
ipn [44]
Answer: k = -1/3

Step-by-Step Explanation:

=> 3x - 2ky + 4 = 0
Value of ‘x’ = -2
Value of ‘y’ = 3

Substitute values of ‘x’ and ‘y’ :-
=> 3x - 2ky + 4 = 0
= 3(-2) - 2k(3) + 4 = 0
= -6 - 6k + 4 = 0
= -6k = 6 - 4
= -6k = 2
= k = 2/-6
=> k = -2/6 = -1/3

Therefore, k = -1/3
8 0
2 years ago
What is (3x+6y-4)+2(x-6) simplified
alekssr [168]

5x+6y-16

Hope this helps...Mark brainliest please


4 0
3 years ago
Read 2 more answers
The sun produces 3.9 ⋅ 10 to the 33th power ergs of radiant energy per second. How many ergs of radiant energy does the sun prod
arlik [135]
So the sun produces 3.9x10³³/ second

Using this ratio (3.9x10³³/ second) we can use the porpotions to calculate time taken (T) to produce 1.55x10⁷.

\frac{3.9(10^3) ergs}{1 second} =  \frac{1.55(10^7)ergs}{T}

Then isolate T and find the time

\frac{T3.9(10^3)ergs}{1 second} = {1.55(10^7)ergs
T3.9(10^3)ergs = ({1.55(10^7)ergs)seconds
T =  \frac{(1.55(10^7)ergs)seconds}{3.9(10^3)ergs}
T =  \frac{(1.55(10^7)seconds}{3.9(10^3)}
T = \frac{1.55}{3.9}(10^4)seconds
T = 0.397(10^4)seconds
T = 3.97(10^-^1)(10^4)seconds
T = 3.97(10^3)seconds

Thus it took 3.97x10³ seconds for 1.55x10⁷. of ergs to be produced
Hope that helped and if it did, a Brainliest rating would be much appreciated


6 0
3 years ago
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