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Lemur [1.5K]
3 years ago
13

Consider today’s stock listing for Enam Telecom, shown below. 52 wk High 52 wk Low Symbol Div. Close Net Change 122.86 64.77 ENM

3.45 99.14 4.74 If the lowest price in the past year occurred 48 days ago, find the approximate average change per day since then.
Mathematics
1 answer:
Alja [10]3 years ago
8 0

Answer:

Average change per day is 0.72

Step-by-step explanation:

As per stock listing given in the listing for Enam Telecom is

52 wk high = 122.86

52 wk low = 64.77

Div. = 3.45

Close = 99.14

Net change = 4.74

Now it is given that lowest price which was 64.77 occurred 48 days ago.

Since yesterday closing price was 99.14 therefore net change in value will be = 99.14 - 64.77 = 34.37

This change is in 48 days so average change per day will be = Total change /number of days = 34.37/48 = 0.716 = 0.72

Answer is average change per day is 0.72

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andreev551 [17]

Answer:

<em>A ≈ 28.5</em>

Step-by-step explanation:

a, b, c

P = a + b + c

Semiperimeter s = \frac{a+b+c}{2}

A = \sqrt{s(s-a)(s-b)(s-c)}

~~~~~~~~~~~~~~~

P_{ABC} = 4.3 + 2.89 + 6.81 = 14

s = 14 ÷ 2 = 7

A_{ABC} = \sqrt{7(7-4.3)(7-2.89)(7-6.81)} = √14.75901 ≈ 3.84

P_{BCD} = 8.59 + 7.58 + 6.81 = 22.98

s = 22.98 ÷ 2 = 11.49

A_{BCD} = \sqrt{11.49(11.49-8.59)(11.49-7.58)(11.49-6.81)} = √609.7343148 ≈ 24.6928

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Please help me with this, thank you so much!!
nirvana33 [79]

Answer:

a. 55.5

b. 12

Step-by-step explanation:

a. 94+17=111

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