Basically, you just have to find the length of the rectangle that is 27 x 78 feet.
The equation for the diagonal:
d = sqrt(l^2+w^2)
l = 27
w = 78
plug them in and solve
d = sqrt ( (27^2) + (78^2) )
d = sqrt ( 729 + 6084 )
d = sqrt ( 6813 )
d <span>≈ 82.5
The ball traveled approximately 82.5 feet from one corner of the rectangular 27 x 78 foot field, diagonally to the other side.
Hope this helps</span>
Let's the name the first number x and the consecutive number x + 1. The sum of both of these numbers equals to 53.
We now have our equation:
x + x + 1 = 53
Now solve for x.
x + x + 1 = 53
2x + 1 = 53 <-- Combine like terms
2x = 52 <-- Subtract 1 from each side
x = 26
So, the first number is 26 and the second number is 27.
Answer:
31 feet.
Step-by-step explanation:
It is mentioned in the question that
Height of baseball expressed in feet
T = time in seconds
Also
Now the time is 3.5 so put this value to the above equation
h = -16(3.5)^2 + 64(3.5) + 3
= -16(2.25) + 224 + 3
= -196 + 227
= 31
Therefore the height of a baseball is 31 feet and the same is to be considered
Answer:
51 inches (or 4 feet 2 inches)
Step-by-step explanation:
if she was 44 inches at the start of second grade, grew 4 inches through second, then grew 3 more inches through third grade, she would be 51 inches (Or 4 feet 2 inches)
