Answer:
![\sf A) \ (-4, \ 0) \ and \ \ [\dfrac{5}{2} , \ 0]](https://tex.z-dn.net/?f=%5Csf%20A%29%20%5C%20%28-4%2C%20%5C%200%29%20%5C%20and%20%5C%20%5C%20%20%5B%5Cdfrac%7B5%7D%7B2%7D%20%2C%20%5C%200%5D)
Explanation:
Given function: f(x) = -2x² - 3x + 20
To find the x-intercepts of a function, f(x) = 0
=================
-2x² - 3x + 20 = f(x)
-2x² - 3x + 20 = 0
-2x² - 8x + 5x + 20 = 0
-2x(x + 4) + 5(x + 4) = 0
(-2x + 5) (x + 4) = 0
-2x + 5 = 0, x + 4 = 0
-2x = -5, x = -4
x = -5/-2,x = -4
x = 5/2, x= -4
Coordinates: (-4, 0), (5/2, 0)
XY - X + 2Y -2 =X(Y-1) + 2(Y-1) = 2X(Y-1)
Answer:
Option C.
Step-by-step explanation:
Shortest way to solve this question is to find the factors of the given expression.
The given expression is (x² + 13).
Now we have to factorize it.
(x² + 13) = x² + (√13)²
= x² + [-(i)²√(13)²] [Since i = √(-1)]
= x² - (i√13)²
= (x - i√3)(x + i√3) [Since (a² - b²) = (a + b)(a - b)]
Option C will be the answer.
Answer:
<u>The only x-intercept is x = 1</u>
Step-by-step explanation:
The equation is:
We can substitute y for r(x), to write in the notation:
To get y-intercept, we put x = 0
and
To get x-intercept, we put y =0
We want to find x-intercepts here, so we substitute 0 into y and solve for x. Shown below:
<u>The only x-intercept is x = 1</u>
Answer:
Step-by-step explanation:
I think it is 22
