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Ivan
3 years ago
14

Solve each equation and check.Show all work.

Mathematics
1 answer:
Anna007 [38]3 years ago
4 0

answer:

s = - 48

explanation:

-s = 2 * 24

-s = 48

which you could re write as s = -48

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Jim believes he will receive 50 pieces of candy for Halloween. If Jim actually received 75 pieces of candy, what is Jim's percen
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33.3

Step-by-step explanation:

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4 years ago
Plz help with this, u don't need to answer all of the questions!
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18. Fran's Funhouse is building a  new claw machine that needs to hold 15 stuffed animals. Each stuffed animal takes up 1,152in( Cubed )amount of space. 
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3 years ago
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valina [46]
♥ Which sets of numbers are closed under addition?



♥ Choose all answers that are correct.



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whole numbers


B.


natural numbers


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D.


<span>integers  
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4 years ago
Read 2 more answers
Lines l and m are parallel to one another and cut by and cut by transversals s and t
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Answer:

you got parallel.  the one look like a x is insterseting  

Step-by-step explanation:

60+40=100

3 0
2 years ago
Two part-time instructors are hired by the Department of Statistics and each is assigned at random to teach a single course in p
scZoUnD [109]

Answer:

The probability that they will teach different courses is \frac{2}{3}.

Step-by-step explanation:

Sample space is a set of all possible outcomes of an experiment.

In this case we will write the sample space in the form (x, y).

Here <em>x</em> represents the course taught by the first part-time instructor and <em>y</em> represents the course taught by the second part-time instructor.

Denote every course by their first letter.

The sample space is as follows:

S = {(P, P), (P, I), (P, S), (I, P), (I, I), (I, S), (S, P), (S, I) and (S, S)}

The outcomes where the the instructors will teach different courses are:

s = {(P, I), (P, S), (I, P),(I, S), (S, P) and (S, I)}

The probability of an events <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

Compute the probability that they will teach different courses as follows:

P(\text{Different courses})=\frac{n(s)}{n(S)}=\frac{6}{9}=\frac{2}{3}

Thus, the probability that they will teach different courses is \frac{2}{3}.

3 0
3 years ago
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