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3 years ago

It costs $15 to send 3 packages through a certain shipping company. Consider the number of packages per dollar

1 answer:

3 0

Let’s find the unit rate of the problem
If we divide both $15 and 3 by 3 we get $5 and 1.
That means every package costs $5, so the COP or k =5
b. Using 5 as the k in y=kx, the equation is y=5x

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Two times the least of three consecutive odd integers exceeds three times the greatest by 15

expeople1 [14]

n, n + 2, n + 4 - three consecutive odd integers

The equation:

2n = 3(n + 4) + 15 |use distributive property

2n = (3)(n) + (3)(4) + 15

2n = 3n + 12 + 15

2n = 3n + 27 |subtract 3n from both sides

-n = 27 |change the signs

n = -27

n + 2 = -27 + 2 = -25

n + 4 = -27 + 4 = -23

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a regional manager is comparing customer satisfaction ratings at two of its stores. 100 customer rattings from each store are ra

zhuklara [117]

Answer:

Yes, there is a significant difference in customer satisfaction ratings at the two stores

The P-value is P=0.000.

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>The store A has a sample mean of 4.05 and a sample standard deviation of 0.039. The store B has a sample mean of 3.99 and a sample standard deviation of 0.025.</em>

We have to perform an hypothesis test for the difference between means.

The claim will state that satisfaction ratings differ. So, the null and alternative hypothesis are:

$H_0: \mu_1-\mu2=0\\\\H_a: \mu_1-\mu2\neq0$

being μ1: the actual staisfaction rating of store A, and μ2: the actual satisfaction rating of store B.

The significance level is 0.05.

We know that, for both samples, the sample size is n=100.

The difference between means is:

$M_d=\mu_1-\mu_2=4.05-3.99=0.06$

The standard error of the diffence between means is calculated as:

$s_M=\sqrt{\dfrac{s_1^2+s_2^2}{n}}=\sqrt{\dfrac{0.039^2+0.025^2}{100}}=\sqrt{\dfrac{0.0021}{100}}=\sqrt{0.000021}=0.0046$

The z-statistic can be calculated as:

$z=\dfrac{M_d-(\mu_1-\mu_2)}{s_M}=\dfrac{0.06-0}{0.0046}=13.04$

The P-value for this test statistic in a two tailed test is

$P-value=2P(z>13.04)=0.000$

The P-value is smaller than the significance level, so the effect is significant. The null hypothesis is rejected.

There is enough evidence that the customer satisfaction rating differs from store A to store B.

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