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emmainna [20.7K]
2 years ago
12

Quick algebra 1 question for some points!

Mathematics
1 answer:
Elanso [62]2 years ago
8 0

\frac{y}{x}  =  \frac{1}{ - 3}  \\  - 3y = x

- 3(2) = 6 = x

<h2>( - 6 , 2 ) </h2><h2>Option a</h2>

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She wants to save 3/5 of 180.00 and spend the rest hpw much would she have left
Anastasy [175]
3/5 of 180 is 108
180-108=72
she would have 72$ left
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3 years ago
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Find the value of x in the triangle shown below 4 3
Solnce55 [7]

Answer: 5

Step-by-step explanation: I took the test

8 0
3 years ago
Consider two functions: g(x)=−x2−6x and the quadratic function ​f(x)​ shown in the table.
S_A_V [24]

Answer:

Hence average rate of change is greater for f(x) in (0,3).

Yes. f(x) is greater than g(x) in the interval (0,3)

Yes. g(3) <f(3)


Step-by-step explanation:

To find average rate of change of f and g in (0,3)

f(3)-f(0)/3 = (9-0)/3 =3

g(3) = -9-18 = -27

g(0) = 0

Rate of change in(0,3) of g(x) = -27/3 =-9

Hence average rate of change is greater for f(x) in (0,3)

---

Both f and g have intercepts of y as 0

Hence both are equal.

3) Yes. f(x) is greater than g(x) in the interval (0,3)

Because g(x) <0 for all x in (0,3) while f(x) >0

4) g(3)= -9-18=-27 <f(3)



5 0
3 years ago
Read 2 more answers
F(x)=6x^2 +10x−1
KATRIN_1 [288]

Answer: It has two distinct real zeros.

Step-by-step explanation:

The formula that is used to calculate the discriminant of a Quadratic function is the one shown below:

D=b^2-4ac

In this case you have the following Quadractic function provided in the exercise:

f(x)=6x^2 +10x-1

Let's make it equal to 0:

0=6x^2 +10x-1

You can identify that:

a=6\\\\b=10

Knowing these values, you can substitute them into the formula and then evaluate:

D=10^2-4(6)(-1)\\\\D=124

Therefore, since:

 D>0

You can determine that the it has two distinct real roots.

3 0
4 years ago
2) Phillip has 8 red balls, 3 green balls, 6 yellow balls, 3 orange balls, 13 black balls
AVprozaik [17]
Mean 6.6
Median 6
Mode 3
Range 10

not positive on the 6.6 but the rest should be good
5 0
3 years ago
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