I Tired To Explain It As Best As I Could.
Isolate the variable by dividing each side by factors that don’t contain the variable.
24 = x • 30
Use The Commutative Property To Reorder The Terms
24 = 30x
Swap The Sides Of The Equations
30x = 24
Divide Both Sides Of The Equations By 30
30x ÷ 30 = 24 ÷ 30
Any Expression Divided By Itself Equals 1
x= 24 ÷ 30 or x =24/30
Reduce The Fraction With 6
x = 4/5
Exact Form:
x = 4/5
Decimal Form:
x = 0.8
Note: I am assuming you meant to say:
- Zoey has 99 beads instead of 99 years.
Answer:
Zoey needs 51 more beads to make 5 bangles.
Step-by-step explanation:
Total number of beads Zoey currently has = 99 beads
Beads need to make one bangel = 30 beads
so
Beads need to make 5 bangles = 30 × 5 = 150 beads
Since she has already 99 beads.
So, all we need s to subtract 99 beads from 150 beads.
Therefore,
The number of beads Zoey needs = 150 - 99
= 51 beads
Thus, Zoey needs 51 more beads to make 5 bangles.
Answer:
-1, 1
13, 15
Step-by-step explanation:
x and x+2 are the integers
- x*(x+2)= 7(x+x+2) -1
- x²+2x= 14x+14-1
- x² - 12x -13= 0
Roots of the quadratic equation are: -1 and 13.
So the integers pairs are: -1, 1 and 13, 15
ANSWER
x = ±1 and y = -4.
Either x = +1 or x = -1 will work
EXPLANATION
If -3 + ix²y and x² + y + 4i are complex conjugates, then one of them can be written in the form a + bi and the other in the form a - bi. In other words, between conjugates, the imaginary parts are same in absolute value but different in sign (b and -b). The real parts are the same
For -3 + ix²y
⇒ real part: -3
⇒ imaginary part: x²y
For x² + y + 4i
⇒ real part: x² + y (since x, y are real numbers)
⇒ imaginary part: 4
Therefore, for the two expressions to be conjugates, we must satisfy the two conditions.
Condition 1: Imaginary parts are same in absolute value but different in sign. We can set the imaginary part of -3 + ix²y to be the negative imaginary part of x² + y + 4i so that the
x²y = -4 ... (I)
Condition 2: Real parts are the same
x² + y = -3 ... (II)
We have a system of equations since both conditions must be satisfied
x²y = -4 ... (I)
x² + y = -3 ... (II)
We can rearrange equation (II) so that we have
y = -3 - x² ... (II)
Substituting into equation (I)
x²y = -4 ... (I)
x²(-3 - x²) = -4
-3x² - x⁴ = -4
x⁴ + 3x² - 4 = 0
(x² + 4)(x² - 1) = 0
(x² + 4)(x-1)(x+1) = 0
Therefore, x = ±1.
Leave alone (x² + 4) as it gives no real solutions.
Solve for y:
y = -3 - x² ... (II)
y = -3 - (±1)²
y = -3 - 1
y = -4
So x = ±1 and y = -4. We can confirm this results in conjugates by substituting into the expressions:
-3 + ix²y
= -3 + i(±1)²(-4)
= -3 - 4i
x² + y + 4i
= (±1)² - 4 + 4i
= 1 - 4 + 4i
= -3 + 4i
They result in conjugates
Answer:
I think-
1. 11
2. 0.7
3. 67.89
4. 13
Step-by-step explanation:
I'm not 100% sure tho
