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Serga [27]
3 years ago
6

if you do this and explain how to do it i will rait you 5 stars and give you a brainlyieist it has to be simplify 2(5+3x)+(x+10)

Mathematics
2 answers:
Paha777 [63]3 years ago
8 0

Answer:

20+7x

Step-by-step explanation:

you'd multiply 2 by 5 and 2 by 3x which will give you 10+ 6x; Then add the others : 2(5+3x)+(x+10) would be 10+6x+x+10 so its 20+7x.     .

Katyanochek1 [597]3 years ago
3 0

Answer: 30+4x or 2(15+2x)

Step-by-step explanation:

So the way you would do this is actually kinda simple.

You question is 2(5+3x)+(x+10)

First you wanna add the common number together. So you would change you problem to

2(5+10)+(x+3x)

Now you want to start by solving 2(5+10)

The two on the outside means you multiply so you would do

2x5+2x10 you would get the answer 10+20=30

Now you’re equation is 30+(x+3x)

So now you need to do (x+3x) in this case we would make X=1

So you do 1+3(1) or 1+(3x1) And you get 4x

Now you have the answer 30+4x or to siplfy it you get 2(15+2x)

Hope this helps you xoxo

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24. A farmstand collected $350 from sales on Wednesday. This amount was $75
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Answer:

$100

Step-by-step explanation:

Given:

  • Wednesday sales = $350

If the amount collected from sales on Wednesday was <u>$75 greater</u> than the amount collected from sales on Tuesday, then Tuesday's sales were $75 <u>less</u> than Wednesday's sales:

  • Tuesday sales = $350 - $75 = $275

If the amount collected from sales on Wednesday was <u>two times as great</u> as the amount collected from sales on Monday, then Monday's sales were <u>half</u> Wednesday's sales:

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Two dice are rolled. Use the complement rule to find that the probability that the sum of the dice is less than 10.
Katarina [22]

Answer:

\dfrac{5}{6}

Step-by-step explanation:

When two dice are rolled, the sample space is

\begin{array}{cccccc}(1,1)&(1,2)&(1,3)&(1,4)&(1,5)&(1,6)\\(2,1)&(2,2)&(2,3)&(2,4)&(2,5)&(2,6)\\(3,1)&(3,2)&(3,3)&(3,4)&(3,5)&(3,6)\\(4,1)&(4,2)&(4,3)&(4,4)&(4,5)&(4,6)\\(5,1)&(5,2)&(5,3)&(5,4)&(5,5)&(5,6)\\(6,1)&(6,2)&(6,3)&(6,4)&(6,5)&(6,6)\end{array}

In total, 36 outcomes

First, find the probability that the sum is 10 or greater:

All favorable outcomes

10: (4,6),\ (5,5),\ (6,4)

11: (5,6),\ (6,5)

12: (6,6)

In total, 6 outcomes.

The probability that the sum is 10 or greater is

P(A)=\dfrac{6}{36}=\dfrac{1}{6}

Use the complement rule to find that the probability that the sum of the dice is less than 10:

P(A^C)=1-P(A)=1-\dfrac{1}{6}=\dfrac{5}{6}

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