H²+10h+21 = 0
h²+3h+7h+21 = 0
h(h+3)+7(h+3) = 0
(h+3)(h+7) = 0
h+3=0
h = -3
h+7=0
h=-7
Answer:
- a) P(x) = 32000*1.04^x
- b) $37435
- c) During year 7
Step-by-step explanation:
<u>Given</u>
- Initial pay = $32000
- Increase rate = 4%
a. <u>Formula</u>
b. Year 5 is after 4 years, so we are looking for the value of P(4)
- P(4) = $32000*1.04^4 = $37435
c. <u>P(x) = 40000, x = ?</u>
- 40000 = 32000*1.04^x
- 1.04^x = 40000/32000
- 1.04^x = 1.25
- log 1.04^x = log 1.25
- x = log 1.25 / log 1.04
- x = 5.69, this is 6 years after
The required number of the years is 6 + 1 = 7
Answer:
the answer should be x=10
The value of the digit 4 in the number 6,028,468 is 100
