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Tamiku [17]
3 years ago
6

An ion is created when __________ are added or removed. A. protons B. neutrons C. electrons D. protons and neutrons

Chemistry
1 answer:
mr_godi [17]3 years ago
4 0

C. electrons

An ion is formed when electrons are gained or lost.

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Repeated trials and replication are the same thing. <br><br> - True<br> - False
Sauron [17]

Answer:

false

Explanation:

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Studying and got stuck if someone can help me.
Lostsunrise [7]

Answer:

Ph level 0-7 is a acid

ph level 7-14 is base

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When lithium reacts with bromine to form the compound LiBr, each lithium atom:
yKpoI14uk [10]
(3) loses one electron and becomes positively charged 
Lithium has one valence electron and Bromine has seven. Therefore Lithium will give up its one to Bromine for both to have an octet 
5 0
3 years ago
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A student lost part of his lab notebook and didn’t know what the original measure should have been. He knows that he calculated
igor_vitrenko [27]
Answer:

21.1cm or 10.1cm

Explanation:

Since the percent error is 35.5% and the experimental measurement was 15.6cm, the two possible values for the actual measurement are 15.6 plus 35.5% of 15.6 or 15.6 minus 35.5% of 15.6.

This is this:

15.6 + (0.355 x 15.6)
= 15.6 + 5.54
= 21.1cm

Or this:

15.6 - (0.355 x 15.6)
= 15.6 - 5.54
= 10.1cm
6 0
3 years ago
A 1.40 L sample of O2 at 645 Torr and 25 °C, and a 0.751 L sample of N2 at 1.13 atm and 25 °C, are both transferred to the same
anyanavicka [17]

Answer:

  • P(O₂) = 0.595 atm
  • P(N₂) = 0.424 atm
  • Total Pressure = 1.019 atm

Explanation:

To solve this problem we use PV=nRT for both gases in their containers, in order to <u>calculate the moles of each one</u>:

  • O₂:

645 Torr ⇒ 645 /760 = 0.85 atm

25°C ⇒ 25 + 273.16 = 298.16 K

0.85 atm * 1.40 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ *298.16 K

n = 0.0487 mol O₂

  • N₂:

1.13 atm * 0.751 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ *298.16 K

n = 0.0347 mol N₂

Now we can <u>calculate the partial pressure for each gas in the new container</u>, because the number of moles did not change:

  • O₂:

P(O₂) * 2.00 L = 0.0487 mol O₂ * 0.082 atm·L·mol⁻¹·K⁻¹ *298.16 K

P(O₂) = 0.595 atm

  • N₂:

P(N₂) * 2.00 L = 0.0347 mol N₂ * 0.082 atm·L·mol⁻¹·K⁻¹ *298.16 K

P(N₂) = 0.424 atm

Finally we add the partial pressures of all gases to <u>calculate the total pressure</u>:

  • Pt = 0.595 atm+ 0.424 atm = 1.019 atm
6 0
4 years ago
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