Answer:
a. Leu-Ala-Arg-Phe-Val-Val-Lys
.
Explanation:
Hello.
In this case, considering the given data, we notice that the amino acid has a N-terminal Leu, that is why we first discard d. Moreover, considering the data (iii) and (v) we can infer that there are going to be two fragments by which it is possible to reason the proper sequence:
(iii): the amino acid has one section composed by Lys-Phe-Val-Val and another one by Ala, Arg, Leu that is why e is also discarded.
(v): the other two fragments are Ala, Arg, Leu, Phe, that is why b is discarded.
(iii) and (v): given the aforementioned fragments, we can combine them and therefore discard c, that is why the correct sequence is:
a. Leu-Ala-Arg-Phe-Val-Val-Lys
.
Best regards.
Answer:
93.5 moles N₂
Explanation:
To find the moles, you need to use the Ideal Gas Law. The equation looks like this:
PV = nRT
In this equation,
-----> P = pressure (atm)
-----> V = volume (L)
-----> n = number of moles
-----> R = constant (0.0821 atm*L/mol*K)
-----> T = temperature (K)
You can plug the given values into the equation and simplify to find moles. The final answer should have 3 sig figs to match the lowest number of sig figs among the given values.
P = 95.0 atm R = 0.0821 atm*L/mol*K
V = 224 L T = 2773 K
n = ?
PV = nRT
(95.0 atm)(224 L) = n(0.0821 atm*L/mol*K)(2773 K)
21280 = n(227.6633)
93.5 = n
Answer:
4 mol of KOH would produce 116.6 g of Mg(OH)₂
Explanation:
According to the following balanced equation:
- MgCl₂+ 2 KOH -----> Mg(OH)₂ + 2 KCL
One can note that 2 mol of KOH react with MgCl₂ to produce 1 mol of Mg(OH)₂.
using cross multiplication
2 mol of KOH → 1 mol of Mg(OH)₂.
4 mol of KOH → ?? mol of Mg(OH)₂.
no of moles of Mg(OH)₂ = (1 mol* 4 mol) / 2 mol =2 mol
Now we can convert moles of Mg(OH)₂ to grams using the formula
mass of Mg(OH)₂= (no. of moles * molar mass) = (2 mol * 58.3g/mol) = 116.6 g
- So, 4 mol of KOH would produce 116.6 g of Mg(OH)₂.
pH: 5.4E-3
pOH: 13.9946
[H+]: 0.987643022777
[OH-]: 1.01251158256E-14 acid
Answer:
B. 4 ham slices
Explanation:
A chemical reaction involves one or more substances known as reactants combining chemically to give one or more substances known as products.
Reactants in chemical reactions combine in definite mole or mass ratios to give products. Therefore, when one substance is present in excess of what is required to combine with another to form products, that substance is known as the excess reagent. The other substance which is present in a smaller amount and which when used up, the reaction stops is known as the limiting reagent.
From the illustration of the sandwiches in the question, the recipe for one sandwich represents the chemical equation of a reaction. The equation form is given below:
2 cheese slices + 1 ham slice + 2 bread slices ---> 1 sandwich
The ratio of the reactant is 2 : 1 : 2
From the available ingredients, 12 cheese slices, 10 ham slices, 12 bread slices.
12 cheese slices will require 6 ham slices and 12 bread slices to produce 6 sandwiches.
However, since there are 10 ham slices, 4 ham slices will be left over unused. This is the excess or leftover reactant.
