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erik [133]
3 years ago
14

How many moles of O2 are contained in 32 grams of O2?

Chemistry
1 answer:
Radda [10]3 years ago
7 0

Answer:

2 moles

Explanation:

In one mole of O2 there are 16 grams. So in 2 moles there are 32 grams

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Liquid does not act that a solid. how is it different from a solid and gas?
Wittaler [7]
Unlike solid matter, where particles are tightly packed and slightly vibrating, or gas, where particles go around everywhere and are extremely loose, a liquid has particles that are loosely packed but are still in slight contact with each other. Hope that's good enough
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Answer this i boot you
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Answer: answer what

Explanation:

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2 years ago
Show your work with good use of units, rounding, and significant figures. [Hint: it is good practice to show the value of your a
mel-nik [20]

Heat required : 4.8 kJ

<h3>Further explanation </h3>

The heat to change the phase can be formulated :

Q = mLf (melting/freezing)

Q = mLv (vaporization/condensation)

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Lv=latent heat of vaporization

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2. phase change(ice to water)

\tt Q=10\times 333=3330~J

3. heat to raise temperature from 0 °C to 25 °C

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3 0
2 years ago
The rate law for the decomposition of phosphine () is It takes 135. s for 1.00 M to decrease to 0.250 M. How much time is requir
vova2212 [387]

Answer:

189.71 secs

Explanation:

We know that decomposition is a first order reaction;

So;

ln[A] = ln[A]o - kt

But;

[A]o = 1.00 M

[A] = 0.250 M

t =135 s

Hence;

ln[A] -  ln[A]o = kt

k = ln[A] -  ln[A]o/t

k = ln(1) - ln(0.250)/135

k =0 - (-1.386)/135

k = 1.386/135

k= 0.01

So time taken now will be;

ln[A] -  ln[A]o = kt

t = ln[A] -  ln[A]o/k

t = ln (3) - ln(0.450)/0.01

t = 1.0986 - (-0.7985)/0.01

t = 1.0986 + 0.7985/0.01

t = 189.71 secs

8 0
2 years ago
For a reversible reaction, what would a large equilibrium constant indicate?
siniylev [52]

(D) At equilibrium, the concentration of the products will be much higher than the concentration of the reactants.

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