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3 years ago

How many moles of O2 are contained in 32 grams of O2?

Chemistry

1 answer:

Radda [10]3 years ago

7 0

Answer:

2 moles

Explanation:

In one mole of O2 there are 16 grams. So in 2 moles there are 32 grams

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Which conversion of energy always occurs in a voltaic cell?

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(4) chemical energy to electrical energy is the correct answer.
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3 years ago

What is the concentration of each type of monosaccharide in lactose

polet [3.4K]

Answer:

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2 years ago

All the following are signs of a chemical reaction, except

hodyreva [135]

C. a change of state. It can be a physical or a chemical state of change.

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3 years ago

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Match the solutions to the descriptions of the freezing points.a. One mole of the ionic compound Na3PO4 dissolved in 1000 g H2O

rosijanka [135]

Explanation:

Depression in Freezing point

= Kf × i × m

where m is molality , i is Van't Hoff factor, m = molality

Since molality and Kf remain the same

depression in freezing point is proportional to i

i= 2 for CuSO4 ( CuSO4----------> Cu+2 + SO4-2

i=1 for C2h6O

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So the freezing point depression is highest for MgCl2 and lowest for C2H6O

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3 years ago

Assume that the test tube shown started out having 10.00 g of mercury(II) oxide. After heating the test tube briefly, you find 1

anyanavicka [17]

This problem is providing information about the initial mass of mercury (II) oxide (10.00 g) which is able to produce liquid mercury (8.00 g) and gaseous oxygen and asks for the resulting mass of the latter, which turns out to be 0.65 g after doing the corresponding calculations.

Initially, it is given a mass of 10.00 g of the oxide and 1.35 g are left which means that the following mass is consumed:

$m_{HgO}^{consumed}=10.00g-1.35 g=8.65 g$

Now, since 8.00 grams of liquid mercury are collected, it is possible to calculate the grams of oxygen that were produced, by considering the law of conservation of mass, which states that the mass of the products equal that of the reactants as it is nor destroyed nor created. In such a way, the mass of oxygen turns out to be:

$m_{O_2}=8.65g-8.00g=0.65g$

Learn more:

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2 years ago