We have that
point C and point D have y = 0-----------> (the bottom of the trapezoid).
point A and point B have y = 4e ---------- > (the top of the trapezoid)
the y component of midpoint would be halfway between these lines
y = (4e+ 0)/2 = 2e.
<span>the x component of the midpoint of the midsegment would be halfway between the midpoint of AB and the midpoint of CD.
x component of midpoint of AB is (4d + 4f)/2.
x component of midpoint of CD is (4g + 0)/2 = 4g/2.
x component of a point between the two we just found is
[(4d + 4f)/2 + 4g/2]/2 = [(4d + 4f + 4g)/2]/2 = (4d + 4f + 4g)/4 = d + f + g.
</span>therefore
the midpoint of the midsegment is (d + f + g, 2e)
Answer:
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Step-by-step explanation:
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Answer:
2√(17) or about 8.2462 units.
Step-by-step explanation:
We want to determine the distance between the two points (-10, -7) and (-8, 1).
We can use the distance formula. Recall that:

Substitute and evaluate:

Hence, the distance between (-10, -7) and (-8, 1) is 2√(17) units or about 8.2462 units.
Answer:
x = -7 1/6
Step-by-step explanation:
x + 4 1/3 = -2 5/6
x = -7 1/6
Answer:
The answer is
<h2>

</h2>
Step-by-step explanation:
The distance between two points can be found by using the formula

where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
(7,2) and (-1, -3)
The distance between them is

We have the final answer as

Hope this helps you