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3 years ago

Calculate the GCF of 36xy and 12xy

Mathematics

1 answer:

Gelneren [198K]3 years ago

7 0

36xy = (12xy)(3)

12xy = (12xy)(1)

GCF(36xy, 12xy) = 12xy

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Please help with these two problems. Show work

MissTica

Answer:

For the first one, it is 1150. For the second one, it is 2460.

Step-by-step explanation:

Think of 23 x 50 as (20 x 50) + (3 x 50).

20 x 50 is 1000. 3 x 50 is 150. 1000 + 150 is 1150.

Think of 30 x 82 as (30 x 80) + (30 x 2)

30 x 80 is 2400. 30 x 2 is 60. 2400+60 is 2460.

3 0

3 years ago

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Find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis. Verify y

mariarad [96]

Answer:

the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis is;

$\frac{\pi }{2} [e^2 - 1 ]$ or 10.036

Step-by-step explanation:

Given the data in the question;

y = $y = e^{(x - 1 )$ , y = 0, x = 1, x = 2.

Now, using the integration capabilities of a graphing utility

y = $y = e_2}^{(x - 1 )_$ , y = 0

Volume = $\pi \int\limits^2_1 ( e^{x-1)^2} - (0)^2 dx$

Volume = $\pi \int\limits^2_1 ( e^{x-1)^2 dx$

Volume = $\pi \int\limits^2_1 e^{2x-2}dx$

Volume = $\frac{\pi }{e^2} \int\limits^2_1 e^{2x}dx$

Volume = $\frac{\pi }{e^2} [\frac{e^{2x}}{2}]^2_1$

Volume = $\frac{\pi }{2e^2} [e^4 - e^2 ]$

Volume = $\frac{\pi }{2} [e^2 - 1 ]$ or 10.036

Therefore, the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis is;

$\frac{\pi }{2} [e^2 - 1 ]$ or 10.036

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3 years ago

A square has a side length of 36 feet the square is dilated by a scale factor of 2/3 do you create a new square what is the side

Ronch [10]

you would multiply 36*2/3 and get 24 which would be the new side length

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3 years ago

1) m SUT equals ___ Degrees.

muminat

Answer:

1. 30

2. 150

3. obtuse

4. acute

5. Adjacent

Step-by-step explanation:

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3 years ago

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Write 504 as a product of powers of its prime factor

34kurt

504 = 2 x 2 x 2 x 3 x 3 x 7

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3 years ago