9. Jack is learning to save, spend, and give his money away to charities. He has determined to give 10% of his summer job earnin
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Use Heron's Formula:
s means semi-perimeter = (50 + 31 + 18) / 2 = 99 / 2 =
49.5
area = sq root [(s * (s-a) * (s-b) * (s-c)]
area = sq root [(49.5 * (s-a) * (s-b) * (s-c)]
This will NOT form a triangle. The longest side (50) is greater than the sum of the other 2 sides.
Source:
http://www.1728.org/trianinq.htm
s means semi-perimeter = (50 + 31 + 18) / 2 = 99 / 2 =
49.5
area = sq root [(s * (s-a) * (s-b) * (s-c)]
area = sq root [(49.5 * (s-a) * (s-b) * (s-c)]
This will NOT form a triangle. The longest side (50) is greater than the sum of the other 2 sides.
Source:
http://www.1728.org/trianinq.htm
The dependent variable is the variable that depends on the value of other variable and keeps on changes with change in the value of one variable. The values given in the table 3 matches the equation and includes the viable solutions.
<h3>Given information-</h3>The number of loaves of bread purchased and the total cost of the bread in dollars can be modeled by the equation,
The quantity of the bread depends on the quantity of the loaves.
<h3>Dependent variable</h3>The dependent variable is the variable that depends on the value of other variable and keeps on changes with change in the value of one variable.
Lets check which table satisfy the above equation.
Table 1-
In the table the first values of the bread and the loves is -2 and -7. The quantity of a bread and loves can not be negative. Thus the table 1 does not provides the viable solution.
Table 2-
In the table 2 the value of the third row is 1.5 loaves and 5.25 breads. Check this by the given equation. When the value of loaves is 1.5 then the value of the bread is,
The value of bread must be 4.5. Thus the table 2 does not provides the viable solutions.
Table 3-
Put the values of the loaves in the given equation one by one,
When the value of loaves is 0 then the value of the bread is,
When the value of loaves is 3 then the value of the bread is,
When the value of loaves is 6 then the value of the bread is,
When the value of loaves is 9 then the value of the bread is,
All the values of the table 3 satisfies the given equation.
Hence, the values given in the table 3 matches the equation and includes the viable solutions.
Learn more about the dependent variables here;