#include<stdio.h>
#include<stdlib.h>
int comment1(FILE *fp)
{
char ch;
int count=0;
while(fscanf(fp,"%c",&ch)!=EOF)
{
if(ch=='\n')
{
return count;
}
count++;
}
return count;
}
int comment2(FILE *fp)
{
char ch;
int count=0;
while(fscanf(fp,"%c",&ch)!=EOF)
{
if(ch=='*')
{
fscanf(fp,"%c",&ch);
if(ch=='/')
{
return count;
}
count++;
}
count++;
}
return 0;
}
int main()
{
printf("Enter the file name:");
char s[1000],ch,ch1;
scanf("%s",s);
FILE*fp;
fp = fopen(s,"r");
int count=0;
while(fscanf(fp,"%c",&ch)!=EOF)
{
if(ch=='\"')
{
while(fscanf(fp,"%c",&ch)!=EOF)
{
if(ch=='\"')
{
break;
}
if(ch=='\\')
{
fscanf(fp,"%c",&ch);
}
}
}
else if(ch=='/')
{
fscanf(fp,"%c",&ch);
if(ch=='/')
{
count += comment1(fp);
}
else if(ch=='*')
{
count += comment2(fp);
}
}
}
printf("%d\n",count);
return 0;
}
Answer:
log base 3a= -0.631.log a/3 base 3
Now, -log m= log 1/m
hence,
log base 3a= 0.631.log 3/a base 3
log base 3a/log 3/a base 3 =0.631
log base 3 ( a.3/a) =.631 since, log m/logn =log n(m)
log base 3 3=0.631
Hence, answer is log base 3 3=0.631
Explanation:
Please check the answer section.
Answer:
FF-FF-FF-FF-FF-FF and 255.255.255.255
Explanation:
FF-FF-FF-FF-FF-FF can be defined as the layer 2 address broadcast which is often used on ethernet frames as well as help to broadcast all equipment due to the fact broadcast is made possible through Ethernet networks in which the Frames are addressed to reach every computer system on a given LAN segment as far as they are addressed to MAC address FF:FF:FF:FF:FF:FF.
255.255. 255.255 can be seen as the layer 3 address which help to address the exact same hosts because it enables the broadcast address of the zero network which is the local network due to the fact that the IP broadcasts are often used by BOOTP and DHCP clients to find and send requests to their respective servers in which a message sent to a broadcast address may be received by all network-attached hosts.
Therefore the Layer 2 and Layer 3 destination addresses which the message contain are FF-FF-FF-FF-FF-FF and 255.255.255.255
Answer:
0-9
Explanation:
count 0 as 1
len(0,1,2,3,4,5,6,7,8,9)=10
Answer:
Webcasts
Explanation:
The rest of the options don't need to be streamed as there isn't a continuous flow of information.