In mathematical analysis, Clairaut's equation is a differential equation of the form where f is continuously differentiable. It is a particular case of the Lagrange differential equation
For the first one just do the multiplication as you do normally.
For the second one, you have to put a zero behind before calculating the numbers in front
Answer:
-7/2
Step-by-step explanation:
Answer:
a = -5
Step-by-step explanation:
Given
-18 + 2a = 2(3a + 1)
Expand the bracket on the right
-18 + 2a = 2 x 3a + 2 x 1
-18 + 2a = 6a + 2
Add 18 to both sides
-18 + 18 + 2a = 6a + 2 + 18
2a = 6a + 20
Subtract 6a from both sides
2a - 6a = 6a - 6a + 20
-4a = 20
Divide both sides by -4
-4a/-4 = 20/-4
a = -5
The answer is 1.144. You can find the answer key in Khan acadmy or even on quizlet
