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olganol [36]
3 years ago
13

explain why the intangibility of software systems poses special problems for software project management.

Computers and Technology
1 answer:
Vaselesa [24]3 years ago
4 0
Unlike other projects like hardware, mechanical works which is tangible it is very easy to identify the progress of the product. But since the product here is software, it is very hard to determine at what phase or progress you are on now. Thus it needs a documentation from someone who are very knowledgeable to be able to know your progress,
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It takes 2 seconds to read or write one block from/to disk and it also takes 1 second of CPU time to merge one block of records.
Alexxx [7]

Answer:

Part a: For optimal 4-way merging, initiate with one dummy run of size 0 and merge this with the 3 smallest runs. Than merge the result to the remaining 3 runs to get a merged run of length 6000 records.

Part b: The optimal 4-way  merging takes about 249 seconds.

Explanation:

The complete question is missing while searching for the question online, a similar question is found which is solved as below:

Part a

<em>For optimal 4-way merging, we need one dummy run with size 0.</em>

  1. Merge 4 runs with size 0, 500, 800, and 1000 to produce a run with a run length of 2300. The new run length is calculated as follows L_{mrg}=L_0+L_1+L_2+L_3=0+500+800+1000=2300
  2. Merge the run as made in step 1 with the remaining 3 runs bearing length 1000, 1200, 1500. The merged run length is 6000 and is calculated as follows

       L_{merged}=L_{mrg}+L_4+L_5+L_6=2300+1000+1200+1500=6000

<em>The resulting run has length 6000 records</em>.

Part b

<u><em>For step 1</em></u>

Input Output Time

Input Output Time is given as

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}

Here

  • L_run is 2300 for step 01
  • Size_block is 100 as given
  • Time_{I/O per block} is 2 sec

So

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}\\T_{I.O}=\frac{2300}{100} \times 2 sec\\T_{I.O}=46 sec

So the input/output time is 46 seconds for step 01.

CPU  Time

CPU Time is given as

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}

Here

  • L_run is 2300 for step 01
  • Size_block is 100 as given
  • Time_{CPU per block} is 1 sec

So

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}\\T_{CPU}=\frac{2300}{100} \times 1 sec\\T_{CPU}=23 sec

So the CPU  time is 23 seconds for step 01.

Total time in step 01

T_{step-01}=T_{I.O}+T_{CPU}\\T_{step-01}=46+23\\T_{step-01}=69 sec\\

Total time in step 01 is 69 seconds.

<u><em>For step 2</em></u>

Input Output Time

Input Output Time is given as

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}

Here

  • L_run is 6000 for step 02
  • Size_block is 100 as given
  • Time_{I/O per block} is 2 sec

So

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}\\T_{I.O}=\frac{6000}{100} \times 2 sec\\T_{I.O}=120 sec

So the input/output time is 120 seconds for step 02.

CPU  Time

CPU Time is given as

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}

Here

  • L_run is 6000 for step 02
  • Size_block is 100 as given
  • Time_{CPU per block} is 1 sec

So

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}\\T_{CPU}=\frac{6000}{100} \times 1 sec\\T_{CPU}=60 sec

So the CPU  time is 60 seconds for step 02.

Total time in step 02

T_{step-02}=T_{I.O}+T_{CPU}\\T_{step-02}=120+60\\T_{step-02}=180 sec\\

Total time in step 02 is 180 seconds

Merging Time (Total)

<em>Now  the total time for merging is given as </em>

T_{merge}=T_{step-01}+T_{step-02}\\T_{merge}=69+180\\T_{merge}=249 sec\\

Total time in merging is 249 seconds seconds

5 0
4 years ago
he Correct Coding Initiative (CCI) edits contain a listing of codes under two columns titled, "comprehensive codes" and "compone
iragen [17]

Answer:

The answer is "Option C"

Explanation:

The content management system promotes the accurate coding technique, which is used to monitor incorrect encoding, in which the comprehensive code is used, that compiles the code to defining or covering two or more CPT part code, packaged as one package, that's why "option c" is correct and other were wrong which can be defined as follows:

  • In option A, It is wrong because code can't be a component code.
  • Option B and Option D is wrong because it uses a comprehensive code only.

7 0
3 years ago
What does an arrow next to a menu item indicate?
katrin2010 [14]
Can you provide a screenshot maybe?
There are many menu items.

4 0
3 years ago
HELP PLEase!!! Which option is an outcome of a project stated in quantifiable terms?
dimulka [17.4K]

Answer: C) a 10 percent increase in efficiency of sales of a particular product line over one year

The term "quantifiable" means that we can attach a number to it. Specifically, a number in which we can do math operations upon it. Something like telephone numbers or serial numbers don't really count as quantifiable entities. They are qualitative variables instead. So you have to be careful what numbers you run into. In this case, "10 percent increase in efficiency" is quantitative and fits what we're after.

A 10% increase corresponds to the multiplier 1.10; for instance, if you had sales of 40 million dollars one year, then a 10% increase is 1.10*40 = 44 million in sales. This is one example where we apply a math operation (specifically multiplication) on the value in question.

4 0
3 years ago
Please Answer Fast will mark Brainliest!!!
vladimir1956 [14]

Answer:

same

Explanation:

3 0
3 years ago
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