The system of rules and structure which governs language is generally referred to as: C. grammar.
<h3>What is language?</h3>
A language simply refers to a structured system of communication through which living organisms, especially humans share information among themselves, especially through the use of spoken words and sounds.
In English language, grammar is the system of rules and structure which governs the use and composition of language.
Read more on language here: brainly.com/question/781903
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Answer:
beacon frame
Explanation:
Beacon frame is a management frame In computer networks, known to be in IEEE 802.11 based WLANs. These frames are transmitted periodically and they contain all the information a station will require before it can rightly transmit a frame.
When it comes to announcing the presence of devices in a wireless computer network (WLAN), Beacon frames are used, and they can also be used in the synchronization of the devices and services
Answer:
because it provides you a lot of storage and the post production equipment to handle it and it is used to do big projects
Explanation:
so l know this much it is correct please mark me brainllest
Shuffle (A[1..m], B[1..n], C[1..m+n]):
Shuf[0, 0] ← True
for j ← 1 to n
Shuf[0, j] ← Shuf[0, j − 1] ∧ (B[j] = C[j])
for i ← 1 to n
Shuf[i, 0] ← Shuf[i − 1, 0] ∧ (A[i] = B[i])
for j ← 1 to n
Shuf[i, j] ← False
if A[i] = C[i + j]
Shuf[i, j] ← Shuf[i, j] ∨ Shuf[i − 1, j]
if B[i] = C[i + j]
Shuf[i, j] ← Shuf[i, j] ∨ Shuf[i, j − 1]
return Shuf[m, n]
The algorithm runs in O(mn) time.
Explanation:
Let, DG is the datagram so, DG= 2400.
Let, FV is the Value of Fragment and F is the Flag and FO is the Fragmentation Offset.
Let, M is the MTU so, M=700.
Let, IP is the IP header so, IP= 20.
Let, id is the identification number so, id=422
Required numbers of the fragment = ![[\frac{DG-IP}{M-IP} ]](https://tex.z-dn.net/?f=%5B%5Cfrac%7BDG-IP%7D%7BM-IP%7D%20%5D)
Insert values in the formula = ![[\frac{2400-20}{700-20} ]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B2400-20%7D%7B700-20%7D%20%5D)
Then, = ![[\frac{2380}{680} ]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B2380%7D%7B680%7D%20%5D)
= ![[3.5]](https://tex.z-dn.net/?f=%5B3.5%5D)
The generated numbers of the fragment is 4
- If FV = 1 then, bytes in data field of DG=
and id=422 and FO=0 and F=1.
- If FV = 2 then, bytes in data field of DG= and id=422 and FO=85
and F=1.
- If FV = 3 then, bytes in data field of DG= and id=422 and FO=170
and F=1.
- If FV = 4 then, bytes in data field of DG=
and id=422 and FO=255
and F=0.
