C. =, the absolute value of a number is always positive
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sen x = 3/5 eleva ao quadrado ambos os lados
sen² x = (3/5)²
Tem que partir da relação fundamental
sen²x + cos²x = 1
(3/5)² + cos² x = 1
cos² x = 1 - (3/5)² = 16/25
cos x = V(16/25 = 4/5
b ) tg x = sen x / cos x = 3/5 / 4/5 = 3/5 * 5/4 = 3/4
c) cotg x = cosx / sen x = 1 / tgx = 1/ (3/4 = 4/3
d) sec x = 1/ cos x = 1 / 4/5 = 5/4
e) cossec x = 1 / sen x = 1/ 3/5 = 5/3
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edson</span>edson <span>· 9 anos atrás</span>
Centimeters would suffice for measuring the length. I hope this helped! :)
Answer:
You can use the midpoint formula, knowing the midpoint between two points (x1,y1) and (x2,y2) has the coordinates
[(x1 + x2)/2, (y1 + y2)/2]
Substituting what we are given, we get:
(2 + x2)/2 = 5 and (5 + y2)/2 = 1
so,
2 + x2 = 10 and 5 + y2 = 2
Solving for x2 and y2 puts the endpoint at (8,-3), which is in the 4th quadrant.
You could also graph the points to get the same result.
Step-by-step explanation:
Answer:
should be 96....I hope it's right
because volume is area of the base × the height × 1/3