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pickupchik [31]
3 years ago
8

A frog is climbing out of a well that is 11 feet deep. The frog can climb 3 feet per hour but then it rests for an hour, during

which it slips back 1 foot. How long will it take for the frog to get out of the well?
Mathematics
1 answer:
Dimas [21]3 years ago
4 0

Answer:

It takes the frog 7 hours to get out of the well.

Step-by-step explanation:

We know that the well is 11 feet deep and the frog can climb 3 feet per hour.

Each time it climbs, it rests for an hour, and decreases its height by 1 foot.

So, if the frog reaches 3 feet in the first hour, then in the next hour it is 2 feet.

Lets calculate with the same pattern:

1st hour: 3 feet

2nd hour: 3-1=2 feet

3rd hour: 2+3=5 feet

4th hour: 5-1=4 feet

5th hour: 4 +3= 7 feet

6th hour: 7-1=6 feet

5th hour: 6+3=9 feet

6th hour: 9-1=8 feet

7th hour:  8+3= 11 feet

Therefore, it takes the frog 7 hours to get out of the well.

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Step-by-step explanation:

The side lengths of the triangle are 3 consecutive integers whose sum (the perimeter) is 42. The average of those integers, 42/3 = 14, is the middle of the three, so they are 13, 14, 15. We're told the perimeter is in inches, so all of these dimensions are inches.

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