A frog is climbing out of a well that is 11 feet deep. The frog can climb 3 feet per hour but then it rests for an hour, during
1 answer:
Answer:
It takes the frog 7 hours to get out of the well.
Step-by-step explanation:
We know that the well is 11 feet deep and the frog can climb 3 feet per hour.
Each time it climbs, it rests for an hour, and decreases its height by 1 foot.
So, if the frog reaches 3 feet in the first hour, then in the next hour it is 2 feet.
Lets calculate with the same pattern:
1st hour: 3 feet
2nd hour: feet
3rd hour: feet
4th hour: feet
5th hour: feet
6th hour: feet
5th hour: feet
6th hour: feet
7th hour: feet
Therefore, it takes the frog 7 hours to get out of the well.
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Answer:
x = ± - 3
Explanation:
I'm assuming you want the solutions to that equation, so here goes! (If not, please comment.)
(x-3)(x+9)=27
Let's FOIL this all out and expand. (Remember: First, Outer, Inner, Last.)
x^2 + 9x - 3x - 27
(first+ inner + outer + last)
x^2 + 9x - 3x - 27 = 27
Combine like terms, and add 27 to both sides.
x^2 + 6x - 27 + 27 = 27 + 27
x^2 + 6x = 54
Let's complete the square, because factoring doesn't work, and because it's good practice.
x^2 + 6x + ___ = 54 + ____
In the blank we will put b/2 ^2 = 6/2 ^2 = 3^2 = 9 to complete the square.
x^2 + 6x + 9 = 54 + 9
Now we've got a perfect square factor:
(x + 3)^2 = 63
sqrt(x+3)^2 =
x + 3 = ±
x = ± - 3
Exact form: x=7/6
Decimal form: x=1.16
Mixed number form: x=1 1/6
Decimal form: x=1.16
Mixed number form: x=1 1/6
Given:
The point is B(2,5) and its image is B'(1,2.5).
To find:
The scale factor.
Solution:
If a figure is dilated by the scale factor k and (0,0) is the center of then the scale factor is defined as
x-coordinate of point B' is 1 and the x-coordinate of point B is 2. So, the scale factor is
Therefore, the scale factor is and the correct option is D.