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sesenic [268]
3 years ago
7

Five boxes of crackers cost 9$. At this rate, how much do 20 boxes cost?

Mathematics
2 answers:
valina [46]3 years ago
6 0

Answer:36

Step-by-step explanation: first I did

9÷5=1.80 per box.

so then I did 1.80 x 20 which = 36

GarryVolchara [31]3 years ago
6 0

Answer:

20 boxes cost $36

Step-by-step explanation:

Using proportions,

5 boxes cost 9$

20 boxes cost X$

Cross multiply

X = 9/5 * 20 = 36$

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BaLLatris [955]
Solve for x or y or 1
solving for y
divide both sides by x
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ok, solve for something else
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this doesn't fit into the standard forms of any of the conic sections
if we were to subsitute points we would see it is a hyperbola that is diagonal with the x and y axises as assemtots

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3 years ago
Dawn comma Sergio comma Tyrone comma and Jim have all been invited to a dinner party. They arrive randomly and each person arriv
professor190 [17]

Answer:

a. 24

b. 2

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Step-by-step explanation:

a.

The first "slot" of person to arrive has 4 possibilities, then the second "slot" will have 3 possibilities, as one has already arrived, then the third "slot" has 2 possibilities, and the fourth "slot" has just 1 possibility.

So, multiplying all these combinations, we have 4*3*2*1 = 24 possible ways they can arrive

b.

If the first and the last person are already "locked", we just have possibilities for the second and third person. The second will have 2 possibilities (Sergio or Tyrone), and the third will have only 1 (the person that wasn't the second between Sergio and Tyrone). So, the number of possibilities is 2*1 = 2

c.

If we have 2 cases where Dawn is first and Jim is last, from a total of 24 possible cases, the probability is 2/24 = 1/12 = 0.0833 = 8.33%

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3 years ago
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Lelechka [254]
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2 years ago
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