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Rama09 [41]
3 years ago
9

Exercise 2.4.2: Proving statements about rational numbers with direct proofs. About Prove each of the following statements using

a direct proof. (a) The product of two rational numbers is a rational number. Solution (b) The quotient of a rational number and a non-zero rational number is a rational number. Solution (c) If x and y are rational numbers then is also a rational number.
Mathematics
1 answer:
IgorLugansk [536]3 years ago
8 0

Answer:

See Explanation

Step-by-step explanation:

(a) Proof: Product of two rational numbers

Using direct proofs.

Let the two rational numbers be A and B.

Such that:

A = \frac{1}{2}

B = \frac{2}{3}

The product:

A * B = \frac{1}{2} * \frac{2}{3}

A * B = \frac{1}{1} * \frac{1}{3}

A * B = 1 * \frac{1}{3}

A * B = \frac{1}{3}

Proved, because 1/3 is rational

(b) Proof: Quotient of a rational number and a non-zero rational number

Using direct proofs.

Let the two rational numbers be A and B.

Such that:

A = \frac{1}{2}

B = \frac{2}{3}

The quotient:

A / B = \frac{1}{2} / \frac{2}{3}

Express as product

A / B = \frac{1}{2} / \frac{3}{2}

A / B = \frac{1*3}{2*2}

A / B = \frac{3}{4}

Proved, because 3/4 is rational

(c) x + y is rational (missing from the question)

Using direct proofs.

Let x and y be

Such that:

x = \frac{1}{2}

y = \frac{2}{3}

The sum:

x + y = \frac{1}{2} + \frac{2}{3}

Take LCM

x + y = \frac{3+4}{6}

x + y = \frac{7}{6}

Proved, because 7/6 is rational

<em>The above proof works for all values of A, B, x and y; as long as they are rational values</em>

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Question:

Simplify the radical expressions

1.\ \sqrt{63     2.\ \sqrt{48    3.\ \sqrt{75      4.\ \sqrt{99      5.\ \sqrt{92

6.\ \sqrt[3]{24}      7.\ \sqrt[3]{81}      8.\ \sqrt{128}     9.\sqrt[3]{40}     10.\ \sqrt[3]{135}

Answer:

\sqrt{63}= 3 \sqrt7

\sqrt{48} = 4\sqrt{3}

\sqrt{75} = 5\sqrt{3}

\sqrt{99} = 3 \sqrt{11

\sqrt{92} = 2\sqrt{23

\sqrt[3]{24} = 2 \sqrt[3]{3}

\sqrt[3]{81} =3\sqrt[3]{3}

\sqrt{128} = 8 \sqrt{2}

\sqrt[3]{40} = 2 \sqrt[3]{5}

\sqrt[3]{135} =3\sqrt[3]{5}

Step-by-step explanation:

1.\ \sqrt{63    

Express 63 as 9 * 7

\sqrt{63}= \sqrt{9 * 7

Split:

\sqrt{63}= \sqrt{9} * \sqrt7

\sqrt{63}= 3 * \sqrt7

\sqrt{63}= 3 \sqrt7

2.\ \sqrt{48    

Express 48 as 16 * 3

\sqrt{48} = \sqrt{16*3}

Split

\sqrt{48} = \sqrt{16}*\sqrt{3}

\sqrt{48} = 4*\sqrt{3}

\sqrt{48} = 4\sqrt{3}

3.\ \sqrt{75    

Express 75 as 25 * 3

\sqrt{75} = \sqrt{25*3}

Split

\sqrt{75} = \sqrt{25}*\sqrt{3}

\sqrt{75} = 5\sqrt{3}

4.\ \sqrt{99  

Express 99 as 9 * 11

\sqrt{99} = \sqrt{9} * \sqrt{11}

Split

\sqrt{99} = 3 \sqrt{11

5.\ \sqrt{92

Express 92 as 4 * 23

\sqrt{92} = \sqrt{4} * \sqrt{23

\sqrt{92} = 2* \sqrt{23

\sqrt{92} = 2\sqrt{23

6.\ \sqrt[3]{24}    

Express 24 as 8 * 3

\sqrt[3]{24} = \sqrt[3]{8} * \sqrt[3]{3}

Express 8 as 2^3

\sqrt[3]{24} = \sqrt[3]{2^3} * \sqrt[3]{3}

\sqrt[3]{24} = 2 \sqrt[3]{3}

7.\ \sqrt[3]{81}

Express 81 as 27 * 3

\sqrt[3]{81} =\sqrt[3]{27}*\sqrt[3]{3}

Express 27 as 3^3

\sqrt[3]{81} =\sqrt[3]{3^3}*\sqrt[3]{3}

\sqrt[3]{81} =3\sqrt[3]{3}

8.\ \sqrt{128}    

Express 128 as 64 * 2

\sqrt{128} = \sqrt{64} * \sqrt{2}

\sqrt{128} = 8 \sqrt{2}

9.\sqrt[3]{40}

Express 40 as 8 * 5

\sqrt[3]{40} = \sqrt[3]{8} * \sqrt[3]{5}

\sqrt[3]{40} = \sqrt[3]{2^3} * \sqrt[3]{5}

\sqrt[3]{40} = 2 \sqrt[3]{5}

10.\ \sqrt[3]{135}

Express 135 as 27 * 5

\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}

Express 27 as 3^3

\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}

\sqrt[3]{135} =3\sqrt[3]{5}

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