The answer is C
I did this test yesterday
Answer:
Bonds: $42,000
Certificates of deposit: $41,000
Step-by-step explanation:
Total invested = Amount in bonds + Amount in CDs
Amount in bonds = Amount in CDs + 1000
Let the amount in bonds = B and the amount in CDs = C
1. 83,000 = B + C
2. B = C+1000
Since the above expression (#2) defines B, you can substitute it for the B in the first equation (#1).
83,000 = C + 1000 + C
Now, you can solve for C.
83,000 = 2C + 1000
82,000 = 2C
41,000 = C
You know that the amount invested in bonds is $1000 greater than the amount invested in CDs, so add $1000 to C and you find B, $42,000.
Answer:
4 parameters are necessary to specify all solutions and correspond to the number of free variables of the system.
Step-by-step explanation:
Remember that the number of free variables of a system is equal to m-rank(A) where m is the number of unknowns variables and A is the matrix of the system.
Since the system is consistent and the rank of the matrix is 3 then echelon form of the augmented matrix has two rows of zeros.
Then m-rank(A)=7-3=4.
Option A. is a function...
here For different values of x in Domain of(x,y) ;There is a unique image y in codomain.
All others have more than one image for a single value x.
Hope it helps...
Regards;
Leukoniv/Olegion.
Step-by-step explanation:
Given,
length of rectangle(l)= 8cm
area of rectangle(A) = 48cm2
breadth of rectangle(b) = ?
Perimeter of rectangle (P)=?
We know ,
Area of rectangle(A) = l×b
or, 48cm2 = 8cm×b
or, 48cm2 = 8bcm
or, 48cm2/8cm = b
or, 6cm = b
or, b = 6cm
therefore, b = 6cm
Perimeter of rectangle (P) = 2(l+b)
= 2(8cm+6cm)
= 2×14cm
= 28cm
therefore, Perimeter of rectangle(P) = 28cm
Now,
According to the question,
Perimeter of rectangle(P) = Perimeter of square(P)
So,
Perimeter of square(P) = 28cm
length of square(l) = ?
Area of square (A) = ?
We know,
Perimeter of square (P) = 4l
or, 28cm = 4l
or, 28cm/4 = l
or, 7cm = l
or, l = 7cm
therefore, l = 7cm
Now,
Area of square (A) = l^2
= (7cm)^2
= 7cm×7cm
= 49cm^2
therefore, area of square (A)= 49cm^2