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valina [46]
2 years ago
10

In an isosceles triangle the length of the base is 10 cm

Mathematics
1 answer:
lawyer [7]2 years ago
5 0

The computation shows the radius of the circle that is inscribed in the isosceles triangle will be 3.33cm.

<h3>How to calculate the radius?</h3>

From the information given, the isosceles triangle the length of a base is 10 cm and the length of a leg is 13 cm.

Let A = area of the triangle

Let S = semi perimeter of the triangle.

The radius will be: = A/S

where,

S = \dfrac{(a + b + c)}{2} = \dfrac{(13 + 13 + 10)}{2} = 18

The radius will be:

 =\dfrac{(\sqrt{18} - \sqrt{13})(\sqrt{18} - \sqrt{13})(\sqrt{18} - \sqrt{10})} { 18}

= 3.33cm

In conclusion, the radius is 3.33cm.

Learn more about triangles on:

brainly.com/question/17335144

#SPJ4

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<h3>What are acute angles?</h3>

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This means that acute angles are less than 90 degrees.

<h3>The real life scenarios</h3>

The real life scenarios that involve acute angles are scenarios that whose measure of angle is less than 90 degrees.

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