Answer:
a) Dependent
b) H0: µd = 0
     Ha: µd > 0
c)  Stat  --> Basic Statistics ----> Paired t. then select samples 1 , 2 to get the required output
d) Not enough data
Step-by-step explanation:
<u>Using values found in MINITAB 19 </u>
a) The samples are dependent and this is because the title of the test is the same ( i.e. A group of students given the LSAT )
<u>b) Appropriate hypothesis</u>
H0: µd = 0
Ha: µd > 0
<u>c) The Minitab procedure to be used to test the hypothesis is </u>
click on Stat  --> Basic Statistics ----> Paired t. then select samples 1 , 2 to get the required output
d) Not enough data to create a probability plot
 
        
             
        
        
        
Answer:
There is a  2/3  probability that the other side is also black.
Step-by-step explanation:
Here let B1: Event of picking a card that has a black side
B2: Event of picking a card that has BOTH black side.
Now, by the CONDITIONAL PROBABILITY:

Now, as EXACTLY ONE CARD has both sides BLACK in three cards.
⇒ P (B1 ∩ B2) = 1 /3
Also, Out if total 6 sides of cards, 3 are BLACK from one side.
⇒ P (B1 ) = 3 /6 = 1/2
Putting these values in the formula, we get:

⇒ P (B2 / B1)  =  2/3
Hence, there is a  2/3  probability that the other side is also black.
  
 
        
             
        
        
        
Start by multiplying 15 by 5, and you get 75. then subtract that from 82, and you get 7. Since you are below the surface, the number is negative. So you get -7. 
        
                    
             
        
        
        
Answer:
huh??
Step-by-step explanation:
 
        
                    
             
        
        
        
Answer:
my best guess would be H
Step-by-step explanation:
3.3 x 3.3 = 9.9 which is close to 10