Question

Use the quadratic formula to solve x^2-6x+5. Show ALL your work

Answer 1

Answer: x = 5, x = 1

Step-by-step explanation:

   x² - 6x + 5

a=1  b=-6  c=5

The quadratic formula is:

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-6)\pm\sqrt{(-6)^2-4(1)(5)}}{2(1)}\\\\\\x=\dfrac{6\pm\sqrt{36-20}}{2}\\\\\\x=\dfrac{6\pm\sqrt{16}}{2}\\\\\\x=\dfrac{6\pm4}{2}\\\\\\x=\dfrac{6+4}{2}\qquad \qquad x=\dfrac{6-4}{2}\\\\\\x=\dfrac{10}{2}\qquad \qquad \qquad x=\dfrac{2}{2}\\\\\\\large\boxed{x=5}\qquad \qquad \quad \large\boxed{x=1}$

Answer 2

Answer:

x=1  or x=5

Step-by-step explanation:

Given Equation

$x^2-6x+5$

Making the equation in standard form:

$x^2-6x+5=0$

Making the factor of the equation:

$x^2-x-5x+5=0$

Taking common from the equation:

$x(x-1)-5(x-1)=0$

$(x-1)(x-5)=0$

Equating the values:

$x-1=0\\\\x=1$

OR

$x-5=0\\\\x=5$