y = ax - b gives the height y of an angled ladder, x ft from its base. Find a formula for x in terms of y.
1 answer:
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Answer:
Step-by-step explanation:
take angle C as reference angle
using tan rule
tan C=oppposite/adjacent
tan C=6/12
tan C=0.5
C=0.5
C=26.6 degree
Your answer is B, two complex roots and two real roots.
By factoring the original equation(which is a difference of two squares), you get:
Because first root is also a difference of two squares, it factors into x - 3 and x +3, your two real roots.
When you factor the second root, the roots are x - 3i and x + 3i.
To prove this, let's multiply them back together:
![[(x-3)(x+3)][(x-3i)(x+3i)]=0\\\\(x^{2}+3x-3x-9)(x^{2}+3xi-3xi-9i^{2})=0\\\\(x^{2}+0x-9)(x^{2}+0xi-9(-1))=0\\\\(x^{2}-9)(x^{2}+9)=0\\\\x^{4}+9x^{2}-9x^{2}-81=0\\\\x^{4}-81=0](https://tex.z-dn.net/?f=%5B%28x-3%29%28x%2B3%29%5D%5B%28x-3i%29%28x%2B3i%29%5D%3D0%5C%5C%5C%5C%28x%5E%7B2%7D%2B3x-3x-9%29%28x%5E%7B2%7D%2B3xi-3xi-9i%5E%7B2%7D%29%3D0%5C%5C%5C%5C%28x%5E%7B2%7D%2B0x-9%29%28x%5E%7B2%7D%2B0xi-9%28-1%29%29%3D0%5C%5C%5C%5C%28x%5E%7B2%7D-9%29%28x%5E%7B2%7D%2B9%29%3D0%5C%5C%5C%5Cx%5E%7B4%7D%2B9x%5E%7B2%7D-9x%5E%7B2%7D-81%3D0%5C%5C%5C%5Cx%5E%7B4%7D-81%3D0)
We reached the equation we started with, so that means that the roots are:
x + 3,
x - 3,
x + 3i, and
x - 3i,
two of which are real and two are complex.
By factoring the original equation(which is a difference of two squares), you get:
Because first root is also a difference of two squares, it factors into x - 3 and x +3, your two real roots.
When you factor the second root, the roots are x - 3i and x + 3i.
To prove this, let's multiply them back together:
We reached the equation we started with, so that means that the roots are:
x + 3,
x - 3,
x + 3i, and
x - 3i,
two of which are real and two are complex.
Part A
Answer: Choice D)
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Explanation:
Let E be the intersection point of the diagonals. For any parallelogram, the diagonals bisect each other. This means that AE = EC = 2n+5 and it also means EB = DE = 4n-3
Focus on triangle AED. This triangle is a right triangle with angle AED as a 90 degree angle (any rhombus has its diagonals that are perpendicular to one another). The legs of this triangle are AE = 2n+5 and ED = 4n-3
Apply the pythagorean theorem to find hypotenuse AD
This points to choice D as the final answer.
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Part B
<h3>Answer: 7.07</h3>-----------------------------------------------
Explanation:
If AC = 14, then half of this is AE = 7. The diagonals bisect each other, so they cut each other in half with E at the midpoint.
Since AE = 2n+5, we can solve for n like so
2n+5 = 7
2n = 7-5
2n = 2
n = 2/2
n = 1
Then we can find the length of AD
Segment AD is roughly 7.07 units long. The other external sides of the rhombus (AB, BC and CD) are also this length because the four sides of any rhombus are the same length.