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ASHA 777 [7]
3 years ago
13

Please help me solve. x^2-11x+19= -5

Mathematics
2 answers:
guajiro [1.7K]3 years ago
6 0
X^2-11x+19=-5
So at first this is a quadratic equation
So h have to make that the equation equal 0 so X^2-11x+19=-5
+5 to other side

X^2-11x+19+5=0
X^2-11x+24=0
Open to bracket
Solve by factorizing
(X-8) (x-3)
So x = 8 or x=3


Eddi Din [679]3 years ago
4 0

Answer:

x = 3 or x = 8

Step-by-step explanation:

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Answer:

P(A) = \frac{30}{100}

P(B) = \frac{77}{100}

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Step-by-step explanation:

Given

See attachment for proper format of table

n = 100 --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

In this row:

Yes = 22 and No = 8

So, we have:

n(A) = Yes + No

n(A) = 22 + 8

n(A) = 30

P(A) is then calculated as:

P(A) = \frac{n(A)}{Sample}

P(A) = \frac{30}{100}

Solving (b): P(B)

Here, we only consider data in the Yes column.

In this column:

(1) = 22    (2) = 25 and (3) = 30

So, we have:

n(B) = (1) + (2) + (3)

n(B) = 22 + 25 + 30

n(B) = 77

P(B) is then calculated as:

P(B) = \frac{n(B)}{Sample}

P(B) = \frac{77}{100}

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

This cell is: [Supplier 1][Yes]

And it is represented with; n(A n B)

So, we have:

n(A\ n\ B) = 22

The probability is then calculated as:

P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}

P(A\ n\ B) = \frac{22}{100}

Solving (d): P(A u B)

This is calculated as:

P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)

This gives:

P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}

Take LCM

P(A\ u\ B) = \frac{30+77-22}{100}

P(A\ u\ B) = \frac{85}{100}

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The amount invested in the first account is $9,300 while the amount invested in the second account is $8,800.

<h3>How do we calculate the amount invested?</h3>

Let x represents the amount invested in the first account.

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Substituting for x, we have:

Amount invested in the second account = $9,300 - $500 = $8,800

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